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aniked [119]
4 years ago
10

C^2 = a^2 + b^2 - 2ab cos C make cos C the subject of the formula

Mathematics
1 answer:
Tems11 [23]4 years ago
3 0

Answer:

\frac{c^{2}-a^{2}-b^{2} }{-2ab}=cos C

Step-by-step explanation:

Start with the parts that are more loosely attached to the cos C: the a² and the b², they are only attached with addition, which can be easily undone by subtracting from both sides. That gives you c²-a²-b²=-2abC

Next, since you want to isolate cosC, you will want to divide by everything attached to the cosC by multiplication: (c²-a²-b²)÷(-2ab)=cosC. Then you can neaten it up and put it in fraction form: \frac{c^{2}-a^{2}-b^{2} }{-2ab}=cos C

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Part A

Extend the table so that we have row and column totals as shown in the diagram below.

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Now to the question of independence vs dependence. It all comes down to this: Does the first selection affect the second selection? If so, then we have dependent events. Otherwise the events are independent. Because we put the first selection back (or replaced it with an equivalent order), this means the first selection does not alter the second selection. The two selections effectively exists in their own separate universe so to speak.

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============================================================

Part B

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Note the second fraction has each term drop by 1.

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