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4 years ago

Value of Y in formula shown when X=4/5 Y= 4/x + ✔️x + 0.2 - 5x

Mathematics

2 answers:

olga55 [171]4 years ago

3 0

Answer:

The value of Y is 2.09443

Step-by-step explanation:

We have to find the value of Y for the given value of x.

The equation of Y is given by

$Y=\frac{4}{x}+\sqrt x+0.2-5x$

And the value of x is 4/5. On substituting this value of x in the equation of y, we get

$Y=\frac{4}{\frac{4}{5}}+\sqrt {\frac{4}{5}}+0.2-5\cdot \frac{4}{5}$

$Y=5+\frac{2}{\sqrt5}+0.2-4$

Add/subtract the numbers, we get

$Y=2.09443$

Therefore, the value of Y is 2.09443

statuscvo [17]4 years ago

3 0

The value of Y in equation ${\text{Y}} = \dfrac{4}{x} + \sqrtx + 0.2 - 5x$ is $\boxed{2.10}.$

Further explanation:

Given:

The value of X is ${\text{X}} = \dfrac{4}{5}.$

The equation of Y is ${\text{Y}} = \dfrac{4}{x} + \sqrtx + 0.2 - 5x.$

Explanation:

The given equation of Y is ${\text{Y}} = \dfrac{4}{x} + \sqrtx + 0.2 - 5x.$

The given value of X is ${\text{X}} = \dfrac{4}{5}.$

Substitute $\dfrac{4}{5}$ for $x$ in equation ${\text{Y}} = \dfrac{4}{x} + \sqrtx + 0.2 - 5x.$

$\begin{aligned}{\text{Y}} &= \frac{4}{{\frac{4}{5}}} + \sqrt {\frac{4}{5}} + 0.2 - 5 \times \frac{4}{5} \\&= 5 + \frac{2}{{\sqrt5 }} + 0.2 - 4\\&= 1.2 + \frac{2}{{\sqrt5 }}\\&= 1.2 + 0.90\\&= 2.10\\\end{aligned}$

The value of Y in equation ${\text{Y}} = \dfrac{4}{x} + \sqrtx + 0.2 - 5x$ is $\boxed{2.10}.$

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Answer details:

Grade: High School

Subject: Mathematics

Chapter: Polynomials

Keywords: polynomial, solution, linear equation, quadratic equation, system of equations, solution of the equations, 4x2 = x3 + 2x, roots, roots of equation.

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