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ryzh [129]
3 years ago
12

An excellent swimmer is confident he can judge his speed in the water exactly. He bets he can swim two lengths of a 50-meter Oly

mpic size pool at an average speed of precisely 2 meters per second. On his first lane he is a little bit slow and ends up going at 1.5 meters per second. Which average speed does he have to reach on his second lane to win the bet?
Mathematics
1 answer:
Zolol [24]3 years ago
7 0
(1.5 + x) / 2 = 2 .... multiply both sides by 2
1.5 + x = 2 * 2
1.5 + x = 4
x = 4 - 1.5
x = 2.5 meters per second
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Determine the factors of 4x2 5x − 6 a(4x − 2)(x 3) b(4x − 3)(x 2) c (4x − 6)(x 1) d(4x − 1)(x 6)
Lelu [443]
4x^2 + 5x - 6 = (4x - 3) (x + 2)

You can do it by using the quadratic function to solve 4x^2 + 5x - 6 = 0; the result will be x = 3/4 and x = -2

Then you have to make (x- 3/4) = 0 and (x +2 ) = 0

When you develop x - 3/4 = 0 you get 4x -3 = 0, which means that 4x - 3 is a factor. The other factor is directly x + 2.

Answer: option b: (4x -3)(x + 2)
8 0
3 years ago
Read 2 more answers
A bag of marbles contains 40 red marbles, 54 blue marbles, and 29 yellow marbles. Which of the following represents the ratio of
JulsSmile [24]

Answer:

\frac{29}{40}

Step-by-step explanation:

we know that

To find the ratio of yellow to red marbles, divide the numbers of yellow marbles by the number of red marbles

Let

x----->  the numbers of yellow marbles

y----> he number of red marbles

we have

x=29, y=40

so

\frac{x}{y}=\frac{29}{40}

8 0
3 years ago
Find the angle between the given vectors to the nearest tenth of a degree. u = , v = (2 points)
Liono4ka [1.6K]

Answer:

<h2>3.6°</h2>

Step-by-step explanation:

The question is incomplete. Here is the complete question.

Find the angle between the given vectors to the nearest tenth of a degree.

u = <8, 7>, v = <9, 7>

we will be using the formula below to calculate the angle between the two vectors;

u*v = |u||v| cos \theta

\theta is the angle between the two vectors.

u = 8i + 7j and v = 9i+7j

u*v = (8i + 7j )*(9i + 7j )

u*v = 8(9) + 7(7)

u*v = 72+49

u*v = 121

|u| = √8²+7²

|u| = √64+49

|u| = √113

|v| = √9²+7²

|v| = √81+49

|v| = √130

Substituting the values into the formula;

121= √113*√130 cos θ

cos θ = 121/121.20

cos θ = 0.998

θ = cos⁻¹0.998

θ = 3.6° (to nearest tenth)

Hence, the angle between the given vectors is 3.6°

5 0
3 years ago
Let g (2) = 22 – 5 and h (2) = 22 +1.<br> Find (g+h) (2)
hjlf

Answer:

23 + 17 = 40 :)

8 0
2 years ago
I just need help with the second one.
NISA [10]

Answer:

(90 - y) °

Step-by-step explanation:

Complement of angle A = 90° - y° = (90 - y) °

7 0
2 years ago
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