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ryzh [129]
4 years ago
12

An excellent swimmer is confident he can judge his speed in the water exactly. He bets he can swim two lengths of a 50-meter Oly

mpic size pool at an average speed of precisely 2 meters per second. On his first lane he is a little bit slow and ends up going at 1.5 meters per second. Which average speed does he have to reach on his second lane to win the bet?
Mathematics
1 answer:
Zolol [24]4 years ago
7 0
(1.5 + x) / 2 = 2 .... multiply both sides by 2
1.5 + x = 2 * 2
1.5 + x = 4
x = 4 - 1.5
x = 2.5 meters per second
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Answer:

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Step-by-step explanation:

During upward projection the final velocity is zero, and the gravitational acceleration is -10 m/s² (against the gravity).

Therefore; using the equation;

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Where s is the height h, g is gravitational acceleration, and t is the time and u is the initial velocity u, is 16 ft/s.

Thus; h= 1/2(-10)t² + 16t

We get; h = -5t² + 16t

Therefore; the quadratic equation is 5t² - 16t + h =0

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The rate of change is
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