Answer:
<u>Given circle:</u>
The center is at (4, 0) and the radius is 5 units
<u>Lets find the distance from (7, 2) to the center of the circle:</u>
- <u />
Since d < 5, the point (7, 2) lies <u>inside</u> the circle
<span>From the pythagorean theorem, we know that x^2 and y^2 = 15^2, where x and y, where x is the base moving from the wall and y is the distance of the ladder sliding down. This means that y = sqrt(225 - x^2). Plugging in x = 13 gives us y = 2sqrt(14). Differentiating both sides of the original equations gives us dy/dt = 13 x 4 / 2sqrt(14) = 52/2sqrt(14) = 26/sqrt(14) ft/s.</span>
The error is that 15 was subtracted on the left side when it should’ve been added.
Corrected equation:
27 = n-15
Add 15 to both sides
42 = n
The prime factors are 2, 3, and 5.
Answer:
82.5
Step-by-step explanation:
Step 1: We make the assumption that 200 is 100 % since it is our output value.
Step 2: We next represent the value we seek with x.
Step 3: From step 1, it follows that 100 % = 200.
Step 4: In the same vein, x % = 165 .
Step 5: This gives us a pair of simple equations:
100 % = 200(1).
x % = 165(2).
Step 6: By simply dividing equation 1 by equation 2 and taking note of the fact that both the LHS
(left hand side) of both equations have the same unit (%); we have
100 % / x % = 200/165
Step 7: Taking the inverse (or reciprocal) of both sides yields
x/100 = 165/200
x = 82.5 %
