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seropon [69]
3 years ago
9

Find the inverse function for f(x)=sqrt2x-6 picture below

Mathematics
1 answer:
Olenka [21]3 years ago
6 0

Answer:

y = (x^2 + 6) / 2

Step-by-step explanation:

Original function: \sqrt{2x - 6}

To find the inverse of a function we have to switch the x and y values and solve for y again

x = sqrt (2y-6)

To get rid of a square root we square the square root so:

x^2 = 2y-6

Add 6

x^2 + 6 = 2y

Divide by 2

y = (x^2 + 6) / 2

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The length of the rectangular fence is 4 feet greater than its width. The perimeter of the fence is less than 42 feet. What is t
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Answer: 4 feet < Length < 21 feet

Step-by-step explanation:

From the question, the length of the rectangular fence is 4 feet more than its width and the perimeter of the fence is less than 42 feet. The range of the lengths of the fence will be:

Length is greater than 4 feet (4 feet more than the width. This means that the length must be at least 4 feet) and less than 21 feet i.e the length must be less than 1/2 of the perimeter which is 42/2 = 21. Therefore, the answer will be:

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Cara and John collect baseball cards.Cara has 12 times as many baseball cards as John.Together they have 117 cards.How many card
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Answer:

Cara:108

Step-by-step explanation:

John: x number of cards

Cara: 12 times x number of cards(she has 12 times more cards than John)

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Cara has 12×9 cards, so she has 108 cards.

Hope this was helpful :)

5 0
3 years ago
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The question is:
saul85 [17]
f(x) = \sqrt{x+1} \\ y = \sqrt{x+1} \ or \ y^2 = x+1 \ or \ x = y^2 - 1 \\ Therefore, \ f^{-1}(x)=x^2 - 1

(fof^{-1})(a) = f(f^{-1}(a))=f(a^2-1) \\ =\sqrt{a^2-1+1}=\sqrt{a^2}=a \\  \\ (f^{-1}of)(a)=f^{-1}(f(a))=f^{-1}(\sqrt{a+1})= \\ (\sqrt{a+1})^2-1 = a+1-1 = a

Therefore, (fof^{-1})(a) = (f^{-1}of)(a) = a

8 0
3 years ago
I need help finding the circumference of this circle ​
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Radius times 2 = diameter which would be 10 times 3.14 is 31.4 so it’s 31.4
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