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OverLord2011 [107]
3 years ago
5

Three consecutive odd intergers have a sum of 27. find the integers

Mathematics
1 answer:
Misha Larkins [42]3 years ago
6 0
Solve for x:
x + (x + 2) + (x + 4) = 27
3x + 6 = 27
3x = 27 - 6
3x = 21
3x / 3 = 21 / 3
x = 7
The integers:
x + (x + 2) + (x + 4) = 27
7 + (7 + 2) + (7 + 4) = 27
7 + 9 + 11 = 27
27 = 27

The integers are 7, 9 , 11
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Answer:

2

Step-by-step explanation:

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7 0
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Hi please help me really need it!
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C

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Inessa05 [86]
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7 0
3 years ago
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Maksim231197 [3]

Answer:

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Step-by-step explanation:

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PQ = 17

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To find P:

QR^2 = PQ^2 + PR^2 – 2(PQ)(PR)cos(P)

15^2 = 17^2 + 14^2 – 2(17)(14)cos(P)

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CosP = 260/476

CosP = 0.5462184

P = Cos^-1(0.5462184)

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8 0
3 years ago
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lisov135 [29]
Infinite i think. because the two equations are the same. 
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4 years ago
Read 2 more answers
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