Three consecutive odd intergers have a sum of 27. find the integers

1 answer:

6 0

Solve for x:
x + (x + 2) + (x + 4) = 27
3x + 6 = 27
3x = 27 - 6
3x = 21
3x / 3 = 21 / 3
x = 7
The integers:
x + (x + 2) + (x + 4) = 27
7 + (7 + 2) + (7 + 4) = 27
7 + 9 + 11 = 27
27 = 27

The integers are 7, 9 , 11

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