Question

A zoo in oklahoma charged $22 for adults and $15 for children. During a summer day, 732 zoo tickets were sold, and the total receipts were $12,912. How many child and how many adult tickets were sold?

Answer 1

Answer: Cost of tickets for adults = $22

Cost of tickets for children = $15

Total number of tickets sold = 732

Total receipts = $12,912

Let x be number of adult ticket's sold and y be the number of child ticket's sold.

Therefore, we have:

$x+y=732$       --------------- equation 1

$x=732-y$

Also, we have:

$22 x+15y=12,912$

Now, let's substitute the value of x:

$22 (732-y)+15y=12912$

$16104-22y+15y=12912$

$16104-7y=12912$

$7y=16104-12912$

$7y=3192$

$y=\frac{3192}{7} =456$

Now, let's substitute the value of y=456 in equation 1, we have:

$x+456=732$

$x=732-456$

$x=276$

Therefore, the number of child ticket's sold is 456 and number of adult ticket's sold is 276