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noname [10]
3 years ago
14

Complete each congruency statement and name the rule used. If you cannot show the triangles are congruent from the given informa

tion, leave the triangle's name blank and write CNBD for "Cannot be determined" in place of the rule. b BA ∩ LC = K ∆BLK ≅ ∆ ______ by _______. PLZ ANSWER FAST!!!!!!!!
Mathematics
1 answer:
svlad2 [7]3 years ago
4 0

Answer:

Cannot be determined.

Step-by-step explanation:

The triangle has three different angles which are not congruent. The sides of the two triangle are not equal therefore these triangle are not determined to be congruent. These triangles share their three angles but not the three sides.

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How do you solve 2/3x+15=17? it is confusing. i have been stuck on this problem for a while...
kirill [66]
Find the opposite of adding 15. So it would be subtracting 15. So subtract 15 on both sides. So it would have 2/3x on the left and then 2 on the other side. (2/3x=2) Now find the opposite of multiplying 2/3. It is dividing 23/3. So divide 23/3 on both sides. So multiply 2/3 times 1/2. It would equal 3. x = 3
Hope this helps. :-)
3 0
4 years ago
2x-y=-1 in slope intercept form
AnnyKZ [126]

Answer:

y=-2x+1

Step-by-step explanation:

y=Mx+b is the slope formula. You want to move y over to the other side to get the equation equal to y

4 0
3 years ago
Given: ∆PQR, m∠R = 90° m∠PQR = 75° M ∈ PR , MP = 18 m∠MQR = 60° Find: RQ
tensa zangetsu [6.8K]

Answer:    RQ= 8.99 ( approx)

Step-by-step explanation:

Let MR= x

Since, In triangle, PRQ, tan 75°= \frac{18+x}{RQ}

⇒ RQ=  \frac{18+x}{tan 75^{\circ}}

Now, In triangle MRQ,

tan 60°= \frac{18+x}{RQ}

⇒ RQ=  \frac{x}{tan 60^{\circ}}

On equating both values of RQ,

\frac{18+x}{tan 75^{\circ}}=\frac{x}{tan 60^{\circ}}

⇒\frac{18+x}{x}=\frac{tan 75^{\circ}}{tan 60^{\circ}}

⇒\frac{18+x}{x}=\frac{tan 75^{\circ}}{tan 60^{\circ}}

⇒\frac{18+x}{x}=2.15470053838

⇒18=2.15470053838x-x

⇒x=15.5884572681≈15.60

Thus RQ=8.99999999999≈8.99


6 0
3 years ago
In a figure, OB is the radius of a big semicircle and XB is the radius of the small semicircle. Given that OX = 14 cm, Calculate
oee [108]

Answer:

perimeter of the shaded region = 88 +44+28 =160 cm

Step-by-step explanation:

perimeter of shaded region = length AO + arc OB + arc AB

length AO = radius of bigger circle

radius of bigger circle = OX + OB = 2×radius of smaller circle = 2×14 cm = 28 cm

therefore AO = 28 cm

length of arc oB= half of circumference of smaller circle = \pi×14 = 44 cm

length of arc ab = half of circumference of bigger circle  = \pi×28 =\frac{22}{7}×28= 88

therefore perimeter of the shaded region = 88 +44+28 =160 cm

area of the shaded region = half of area of bigger circle - half of area of smaller circle

                                           =\frac{1}{2} \pi 28^{2} -\frac{1}{2} \pi 14^{2}

                                           =\frac{\pi }{2} (28^{2} -14^{2} )

  solving we gen area of shaded region = 924

7 0
3 years ago
Pls help . <br><br> (when u get in the document its duplicated)
riadik2000 [5.3K]
The picture is not showing up
6 0
2 years ago
Read 2 more answers
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