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bonufazy [111]
3 years ago
13

If the volume is 56 1/4 cubic feet and the length is 7 1/2ft and the width is 3 3/4ft what is the height?

Mathematics
1 answer:
DedPeter [7]3 years ago
3 0
The height is 2. Multiply 7.5 by 3.75 and you should get 28.125. Divide 56.25 by 28.125 and you will get 2. If you want to check, multiply 2 by 7.5 by 3.75 and you will get 56.25.
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HELP PLEASE!
wel

Answers:

\text{Perimeter} = 14\sqrt{5}\\\\\text{Area} = 50\\\\

=======================================================

Work Shown:

L = 2\sqrt{5} = \text{length}

W = 5\sqrt{5} = \text{width}

P = perimeter

P = 2*(L+W)\\\\P = 2*(2\sqrt{5}+5\sqrt{5})\\\\P = 2*(7\sqrt{5})\\\\P = 14\sqrt{5}\\\\

-------------

A = area

A = L*W\\\\A = (2\sqrt{5})*(5\sqrt{5})\\\\A = (2*5)(\sqrt{5}*\sqrt{5})\\\\A = 10\sqrt{5*5}\\\\A = 10\sqrt{25}\\\\A = 10*5\\\\A = 50\\\\

3 0
2 years ago
Read 2 more answers
Can someone do this for me please?!
amm1812
<h3>What are the different parts of a circle? </h3>

The different parts of a circle are radius, diameter, chord, tangent, arc, centre, secant, sector. Write down the circle formulas. If “r” is the radius of the circle, then the formula for the area and the circumference of a circle are:

5 0
2 years ago
Which inequality is true when x = -3?
gulaghasi [49]

Answer:

C)

-5(-3) = 15 therefore the less than/equal too statement stands truest amongst the total inequalities.

4 0
2 years ago
) Determine the probability that a bit string of length 10 contains exactly 4 or 5 ones.
yanalaym [24]

Answer: 0.4512

Step-by-step explanation:

A bit string is sequence of bits (it only contains 0 and 1).

We assume that the  0 and 1 area equally likely to any place.

i.e. P(0)= P(1)= \dfrac{1}{2}

The length of bits : n = 10

Let X = Number of getting ones.

Then , X \sim Bin(n=10,\ p=\dfrac{1}{2})

Binomial distribution formula : P(X=x)=^nC_x p^x q^{n-x} , where p= probability of getting success in each event and q= probability of getting failure in each event.

Here , p=q=\dfrac{1}{2}

Then ,The probability that a bit string of length 10 contains exactly 4 or 5 ones.

P(X= 4\ or\ 5)=P(x=4)+P(x=5)\\\\=^{10}C_4(\dfrac{1}{2})^{10}+^{10}C_4(\dfrac{1}{2})^{10}

=\dfrac{10!}{4!6!}(\dfrac{1}{2})^{10}+\dfrac{10!}{5!5!}(\dfrac{1}{2})^{10}

=(\dfrac{1}{2})^{10}(\dfrac{10!}{4!6!}+\dfrac{10!}{5!5!})

=(\dfrac{1}{2})^{10}(210+252)

=(0.0009765625)(462)

=0.451171875\approx0.4512

Hence, the  probability that a bit string of length 10 contains exactly 4 or 5 ones is 0.4512.

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3 years ago
Factor a^2+6a+6b–b^2 plz
vovangra [49]

Answer:

(a+b) (a-b+6)

4 0
3 years ago
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