The ten's digit of a two digit number is 1 more than 4 times the units' digit. if 63 is subtracted from the number, the order of the digits is reversed. find the number.
1 answer:
Let x be the digit in the tens place and y be the digit in the ones place. so, the digit is xy <span> The ten's digit of a two digit number is 1 more than 4 times the units' digit. </span>x = 4y + 1 <span>63 is subtracted from the number, the order of the digits is reversed </span>10x + y - 63 = 10y + x 9x - 9y = 63 x = 4y + 1 ------------ (1) 9x - 9y = 63 ---------- (2) Sub (1) into (2) 9(4y + 1) - 9y = 63 36y + 9 - 9y = 63 27y = 63 - 9 27y = 54 y = 2 ------- sub into (1) x = 4(2) + 1 = 9 x = 9, y = 2 The number is 92
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