For the answer to the two questions above,
3x + 2y = 36.50 (I)
2x + 5y = 50 (II)
Eliminating x from the two equations by subtraction:
first we multiply equation I by 2 and equation II by 3
6x + 4y = 73
6x + 15y = 150
Subtracting the two,
-11y = -77
y = 7
He earns $7 at the coffee cart
Substituting y into equation I,
3x + 14 = 36.5
x = $7.50
So we can conclude that, he earns a greater wage of $7.50 at the library,
Answer:
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IF Factor x4−10x2+25
x4−10x2+25
=(x2−5)(x2−5)
Answer:
(x2−5)(x2−5)
IF simplify
x4−10x2+25
There are no like terms.
Answer:
=x4−10x2+25
Total Value =$23,000
Time = 10 february to 10 august = 6 months
And
Rate of discount = 9% =0.09
Now we have to find the discount on the note
So we multiply the amount , time and rate
but time should be in years
So 6 months = 6/12 years = 0.5 years
So
Discount = 23,000 * 0.5 * 0.09 = 1035
Hence total Discount = $1035
Answer:
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Answer: Option C. Married and grade 2 (92.6%) is higher than Single and grade 2 (5.2%)
Solution:
Conditional relative frequency single employees in grade 2:
[(Single employees in job grade 2)/(Total employees in job grade 2)]*100%=
(222/4,239)*100%=0.052370842*100%=5.2370842% approximately 5.2%
Conditional relative frequency married employees in grade 2:
[(Married employees in job grade 2)/(Total employees in job grade 2)]*100%=
(3,927/4,239)*100%=0.926397735*100%=92.6397735% approximately 92.6%
92.6%>5.2%:
Married and grade 2 (92.6%) is higher than Single and grade 2 (5.2%)