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Alex_Xolod [135]

3 years ago

14

What is the solution to the system of equations 2x-y=7 and y=2x+3

1 answer:

Yuri [45]3 years ago

6 0

Make y the subject in both equations

$2x-y=7$

$-y=-2x+7$

$y=2x-7$

For the second equation

$y=2x+3$

The two equations are parallel because they have the same gradient or slope but different y intercepts.

This type of equations have no solution because they will never intersect.

$NO SOLUTION$

The correct answer is C

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Enter the equation of the line in slope-intercept form. Slope is -1/2, and (-9,4) is on the line. The equation of the line is y=

dezoksy [38]

Answer:

$y=\displaystyle-\frac{1}{2}x-\displaystyle\frac{1}{2}$

Step-by-step explanation:

Hi there!

Slope-intercept form: $y=mx+b$ where <em>m</em> is the slope and <em>b</em> is the y-intercept (the value of y when x is 0)

<u>1) Plug in the slope (</u><u><em>m</em></u><u>)</u>

We're given that the slope is $\displaystyle-\frac{1}{2}$ . In $y=mx+b$ , replace <em>m</em> with $\displaystyle-\frac{1}{2}$ :

$y=\displaystyle-\frac{1}{2}x+b$

<u>2) Determine the y-intercept (</u><u><em>b</em></u><u>)</u>

$y=\displaystyle-\frac{1}{2}x+b$

We're given the point (-9,4). Plug this point into the equation as $(x,y)$ and solve for <em>b</em>:

$4=\displaystyle-\frac{1}{2}(-9)+b\\\\4=\displaystyle\frac{9}{2}+b$

Subtract $\displaystyle\frac{9}{2}$ from both sides to isolate <em>b</em>:

$4-\displaystyle\frac{9}{2}=\displaystyle\frac{9}{2}+b- \displaystyle\frac{9}{2}\\\\\displaystyle-\frac{1}{2} = b$

Therefore, the y-intercept is $\displaystyle-\frac{1}{2}$ . Plug this back into $y=\displaystyle-\frac{1}{2}x+b$ as <em>b</em>:

$y=\displaystyle-\frac{1}{2}x+(\displaystyle-\frac{1}{2})\\\\y=\displaystyle-\frac{1}{2}x-\displaystyle\frac{1}{2}$

I hope this helps!

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Step-by-step explanation:

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neonofarm [45]

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Step-by-step explanation:

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Evaluate v - t when t = 7x + 4 and v = x - 8

Leni [432]

Answer:

Step-by-step explanation: (7x+4)-(x-8)

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