Ask question

Ask question

All categories

Alex_Xolod [135]

2 years ago

14

What is the solution to the system of equations 2x-y=7 and y=2x+3

1 answer:

Yuri [45]2 years ago

6 0

Make y the subject in both equations

$2x-y=7$

$-y=-2x+7$

$y=2x-7$

For the second equation

$y=2x+3$

The two equations are parallel because they have the same gradient or slope but different y intercepts.

This type of equations have no solution because they will never intersect.

$NO SOLUTION$

The correct answer is C

You might be interested in

If the pattern continues, how many stars will be in the Stage 15 figure?

Paha777 [63]

Answer:

There would be 45 stars in a stage 15 patteren

4 0

3 years ago

What is the value of w in the following proportion?

Ghella [55]

Answer:

im pretty sure its c

Step-by-step explanation:

soryy cant explain

7 0

3 years ago

Read 2 more answers

What is the slope of the line shown below?<br><br> A. -3<br> B.-6<br> C.6<br> D. 3

aniked [119]

Answer:

D.3

Step-by-step explanation:

We are going to use the Slope Formula --> (y2-y1)/(x2-x1)

(9-3)/(3-1)=6/2=3

6 0

3 years ago

How do you solve this: In ?PQR, PQ = 39 cm and PN is an altitude. Find PR if QN = 36 cm and RN = 8 cm.

ikadub [295]

Answer:

PR = 17 cm

Step-by-step explanation:

Given :

In ΔPQR,

PQ = 39 cm

PN is an altitude.

QN = 36 cm

RN = 8 cm.

To Find : Length of PR

Solution :

Since we are given that PN is an altitude .

So, PN divides ΔPQR in two right angled triangles named as ΔPQN and ΔPRN. (Refer attached file)

So, first we find Length of PN in ΔPQN using Pythagoras theorem i.e.

$(Hypotenuse)^{2}=(Perpendicular)^{2} +(Base)^{2}$

$(PQ)^{2}=(PN)^{2} +(QN)^{2}$

$(39)^{2}=(PN)^{2} +(36)^{2}$

$1521=(PN)^{2} +1296$

$1521 -1296=(PN)^{2}$

$225=(PN)^{2}$

$\sqrt{225} = PN$

$15 = PN$

Thus, Length of PN = 15cm

Now to find length of PR we will use Pythagoras theorem in ΔPRN.

$(PR)^{2}=(PN)^{2} +(NR)^{2}$

$(PR)^{2}=(15)^{2} +(8)^{2}$

$(PR)^{2}=225 +64$

$(PR)^{2}=289$

$PR= \sqrt{289}$

$PR= 17$

Hence the length of PR = 17 cm

3 0

3 years ago

Consider this system of equations. Which shows the first equation written in slope-intercept form?

eimsori [14]

Question:

Consider this system of equations. Which shows the first equation written in slope-intercept form?

½(2y + 10) = 7x.

y = 8.

A. y = 7x - 10

B. y = 7x/2 - 5

C. y = 7x - 5

D. y = 7x/4 - 5

Answer:

C. y = 7x - 5

Step-by-step explanation:

Given

½(2y + 10) = 7x.

Required

Convert to slope intercept form.

To do this, we simply make y the subject of formula from the given equation

We start by writing out the equation

½(2y + 10) = 7x.

Then, we open the bracket

½ * 2y + ½ * 10 = 7x

2y/2 + 10/2 = 7x

y + 5 = 7x

Then, subtract 5 from both sides of the equation

y + 5 - 5 = 7x - 5

y = 7x - 5

The equation can't be simplified any further. So, we've arrived at a solution

Hence, the slope intercept form of ½(2y + 10) = 7x is y = 7x - 5

8 0

2 years ago