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kari74 [83]
3 years ago
11

What average speed does he need to reach in his second round in order to attain the overall average speed of 60 mph required for

the test?
Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
3 0
10 think about it it’s 60s and it’s in the ten’s place because 10,20,30,40,50, and 60
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The age difference between the two brothers is 5. 7 years later, the age of the elder brother will be 3 times bigger than the ag
saw5 [17]

Answer:

<em><u>y = 4 and x = 9</u></em>

Step-by-step explanation:

I hope this is correct

6 0
3 years ago
Write the population of lubbok in word form
Shtirlitz [24]
1651384 also known as "one million, six hundred fifty one thousand, three hundred eighty four"
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3 years ago
3. Which rule best describes the last three numbers shown in the pattern? 10, 12, 9, 11​
sergij07 [2.7K]

Answer:

it goes by 2 two times then subtracts 3 then again

Step-by-step explanation:

10,12,9,11,8,10,7

5 0
3 years ago
A student takes an exam containing 1414 multiple choice questions. The probability of choosing a correct answer by knowledgeable
Readme [11.4K]

Answer:

0.0082 = 0.82% probability that he will pass

Step-by-step explanation:

For each question, there are only two possible outcomes. Either the students guesses the correct answer, or he guesses the wrong answer. The probability of guessing the correct answer for a question is independent of other questions. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

n = 14, p = 0.3.

If the student makes knowledgeable guesses, what is the probability that he will pass?

He needs to guess at least 9 answers correctly. So

P(X \geq 9) = P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 9) = C_{14,9}.(0.3)^{9}.(0.7)^{5} = 0.0066

P(X = 10) = C_{14,10}.(0.3)^{10}.(0.7)^{4} = 0.0014

P(X = 11) = C_{14,11}.(0.3)^{11}.(0.7)^{3} = 0.0002

P(X = 12) = C_{14,12}.(0.3)^{12}.(0.7)^{2} = 0.000024

P(X = 13) = C_{14,13}.(0.3)^{13}.(0.7)^{1} = 0.000002

P(X = 14) = C_{14,14}.(0.3)^{14}.(0.7)^{0} \cong 0

P(X \geq 9) = P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) = 0.0066 + 0.0014 + 0.0002 + 0.000024 + 0.000002 = 0.0082

0.0082 = 0.82% probability that he will pass

6 0
3 years ago
Let u = &lt;3, -1&gt;, v = &lt;-6, -6&gt;. Find 9u + 2v.
Gnom [1K]
9u means you're multiplying 9 into that vector, both components.  Same with the 2v.  9*3 = 27 and 9*-1 = -9, so your new vector u is <27, -9>.  Now let's do v.  2* -6 (twice) = -12, so your new v vector is <-12, -12>.  Add those together now, first components of each and second components of each.  27 + (-12) = 15; -9+(-12)=-21.  So the addition of those gives us a final vector with a displacement of <15, -21>
5 0
3 years ago
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