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Ksju [112]
3 years ago
8

I need help quick please! 15 points!

Mathematics
1 answer:
vodka [1.7K]3 years ago
4 0
X = money in the accounts in March

x + 210 = x + 0.15x
210 = 0.15x
210/0.15 = x
1400 = x

check..
Isaah -- 1400 + 210 = 1610
Freddie -- 1400 + 0.15(1400) = 1400 + 210 = 1610

<span>March accounts = $ 1400 </span>
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Given cos theta = - 2/5 and sin theta &lt; 0, find the six trigonometric values. I need help with this
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Answer:

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\tan\,\theta =\frac{\sqrt{21} }{2}

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\cot\,\theta =\frac{2}{\sqrt{21} }

Step-by-step explanation:

\cos\theta =\frac{-2}{5}

As both sin\,\theta,

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In the third quadrant,

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\sin\,\theta =-\sqrt{1-\cos^2\,\theta} \\=-\sqrt{1-(\frac{-2}{5})^2 } \\\\=-\sqrt{1-\frac{4}{25} }\\\\=-\sqrt{\frac{25-4}{25} }\\\\=-\frac{\sqrt{21} }{5}

\tan\,\theta = \frac{\sin\,\theta}{\cos\,\theta }\\\\=\frac{\frac{-\sqrt{21} }{5} }{\frac{-2}{5} }\\\\=\frac{\sqrt{21} }{2}

\sec\,\theta =\frac{1}{\cos\,\theta }\\\\=\frac{1}{\frac{-2}{5} }\\\\=\frac{-5}{2}

\ cosec \,\theta = \frac{1}{sin\,\theta }\\\\=\frac{1}{\frac{-\sqrt{21} }{5} }\\\\=\frac{-5}{\sqrt{21} }

\cot\,\theta =\frac{1}{\tan\,\theta}\\\\=\frac{1}{\frac{\sqrt{21} }{2} }\\\\=\frac{2}{\sqrt{21} }

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