Answer:
<h2>R-{5}</h2>
Step-by-step explanation:
f(x)=x²-25=(x-5)(x+5)
g(x)=x-5
(f/g)(x)=<em>(x-5)</em>(x+5)/<em>(x-5)</em>=x+5; for x≠5
D=R-{5}
This question is very oddly worded. The domain is the set of x-values, but this is a set of (x,y) ordered pairs.
I'm reading this question as "Here's a function, { (1,5), (2,1), (-1,-7) }. If this is reflected over the x-axis, what's the range?"
Assuming that is the question that is meant to be asked, reflecting a function over the x-axis will just change the signs of the y-values.
(1,5) -> (1,–5)
(2,1) -> (2,–1)
(-1,-7) -> (-1,+7)
I'd pick the third option.
9514 1404 393
Answer:
(x, y, z) = (1, 2, 3)
Step-by-step explanation:
The equations that result from reduction to row-echelon form are ...
x = 0.4 +0.2t
y = 5.6 -1.2t
z = t
Then t must have a value 5n+3 for 0 ≤ n < 1. That is, t=3.
x = 0.4 +0.2(3) = 1
y = 5.6 -1.2(3) = 2
z = 3
The integers that satisfy are (x, y, z) = (1, 2, 3).
Step-by-step explanation:
This seems to be calculus 1.
<u>Question a</u>
We have 
m = slope = derivative
Find the derivative / slope of 
We do this by differentiating the polynomials. There are a few methods to do this but I am going to use the power rule, which we multiply the constant by the exponent on the variable and subtract one from the exponent.


when x = a
<em>Now that we have this information, we can answer question b</em>
<u>Question b</u>
<u>The tangent line for Point (1, 12)</u>
First find the slope by using our derivative.

Now that we have our slope, use point slope form to find our tangent line


<u>Now lets do the same for the Point (2, 13)</u>
Find the slope at the point.
Now find the tangent line using point slope form of a line.


Now graph the lines, which I have done and you can see by viewing the image I have attached.