Question

On a coordinate plane, what is the distance between the points (-4, -3) and (-1, 5)? Round your answer to the nearest hundredth.

Answer 1

Answer:

8.54

Step-by-step explanation:

To find the distance between 2 points

d = sqrt( y2-y1)^2 + (x2-x1)^2)

where (x1,y1) and (x2,y2) are the two points

d = sqrt((5--3)^2+ (-1--4)^2)

  = sqrt((5+3)^2+ (-1+4)^2)

  =  sqrt((8)^2+ (3)^2)

   = sqrt(64+ 9)

    =sqrt (73)

    =8.544003745

Rounding to the nearest hundredth

   =8.54

Answer 2

ANSWER

The distance between the two points is 8.54 to the nearest hundredth.

EXPLANATION

We want to find the distance between the the points (-4, -3) and (-1, 5).

We use the distance formula;

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$d=\sqrt{( - 1 - -4)^2+(5- - 3)^2}$

$d=\sqrt{( 3)^2+(8)^2}$

$d=\sqrt{9+64}$

$d = \sqrt{73}$

$d = 8.544$

To the nearest hundredth the distance is 8.54 units.