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hoa [83]
4 years ago
5

How many centimeters are in 2.4 km? a. 240 b. 2400 c. 24,000 d. 240,000

Biology
1 answer:
dem82 [27]4 years ago
4 0
To solve this first we will see how many cm go in 1 km. 

1 km = 100000 cm 

To solve:-

2.4 km = ? cm we will multiply.

2.4 × 100000 = 2.4 km = ? cm 
2.4 × 100000 = 240000

So, 2.4 km = <span>240000</span> cm (d).

Hope I helped ya!! 
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The following is a list of the vessels that blood passes through from the heart back to the heart.The correct order in which blo
slamgirl [31]

Answer:

elastic arteries, muscular artery, arterioles, capillary, venules, medium veins, large veins,

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5 0
4 years ago
What is the energy requirement in kJ/mol to transport a proton across the mitochondrial inner membrane in plant cells at night w
lions [1.4K]

Answer:

C. +23.1 kJ/mol

Explanation:

the formula to use to calculate the energy requirement in kJ/mol to transport a proton across the mitochondrial inner membrane in plant cells is:

ΔGt = RTIn  \frac{C_{2} }{C_1}   + ZFΔV

let's list the values of the data we are being given in the question to make it easier when solving it.

Z= 1

F= 96500C (faraday's constant)

ΔV= 160mV = 0.160V

R= 8.314( constant)

T= 15ºC ( converting our degree Celsius into kelvin, we will have 273.15k+ 15 = 288.15K)

∴ T= 288.15K

Putting it all together in the formula, we have:

ΔGt = 8.314 × 288.15 × 2.303 log \frac{C_{2} }{C_1}  + 1  × 96500 × 0.160

ΔGt = 5517.25   [ -(log(H^{+}_{out} ) + log(H^{+}_{in} )_{in}  +15440

ΔGt  = 5517.25 (pH_{out} - pH_{in}  +15440

Given that the pH  differential gradient  across the membrane is 1.4pH units. It implies that;

ΔGt  = 5517.25 × 1.4 + 15440

=  7724.15 +15440

= 23164.15 Joules/moles

= +23.1 KJ/mole

4 0
4 years ago
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