Hi!
<u>Given these two equations:</u>
![x = y + 8](https://tex.z-dn.net/?f=x%20%3D%20y%20%2B%208)
![x + 4 = 2(y + 4)](https://tex.z-dn.net/?f=x%20%2B%204%20%3D%202%28y%20%2B%204%29)
We want to solve using the substitution method. Knowing that x is equal to y + 8, we can simply plug in 'y + 8' in for x in the second equation, like so:
![(y+8)+4=2(y+4)](https://tex.z-dn.net/?f=%28y%2B8%29%2B4%3D2%28y%2B4%29)
Combine like terms on both sides:
![y+12=2y+8](https://tex.z-dn.net/?f=y%2B12%3D2y%2B8)
Subtract y from both sides:
![12=y+8](https://tex.z-dn.net/?f=12%3Dy%2B8)
Subtract 8 from both sides:
![y=4](https://tex.z-dn.net/?f=y%3D4)
Now, we can simply plug the y value in to the first equation, and solve for x:
![x=4+8](https://tex.z-dn.net/?f=x%3D4%2B8)
Simplify:
![x=12](https://tex.z-dn.net/?f=x%3D12)
<h3>
Therefore, x is equal to 12 and y is equal to 4.</h3>
<u>Learn more about the substitution (and also elimination!) method here:</u>
brainly.com/question/14619835
Answer:
No answer
Step-by-step explanation:
5x-20-X+9
7x-20+9
7x-11
What we have so far:
Kinetic energy = 0. The reason behind that is because the beam is not moving at a height of 40m.
Gavity, g = 9.8m/s²
Height = 40m
Potential energy = mgh; this is equal to 0 because m, stands for mass and in this problem, we do not have a value for the mass of the beam. Hence, 0 x 9.8m/s² x 40m = 0. Potential energy = 0.
Solution:
We will use the equation of Total energy:
TE = potential energy + kinetic energy
TE = 0 + 0
∴ TE = 0
The answer is: Assuming no air resistance, the total energy of the beam as it hits the ground is 0.
x+x+y.y.y = 2x+y^3 ( y cube)
So, The answer is (d)