Answer:
$18500 at 6% and $28500 at 8%
Step-by-step explanation:
Let x represent the amount invested at 6%. Then x+10000 is the amount invested at 8%. The total income from the two investments is the sum of the products of the amount invested and the interest rate:
x·6% +(x+10000)·8% = 3390
0.14x + 800 = 3390 . . . . . . . . collect terms
0.14x = 2590 . . . . . . . . . . . . . .subtract 800
2590/0.14 = x = 18500 . . . . . divide by the coefficient of x
Sue has invested $18500 at 6% and $28500 at 8%.
Given:$7/child
$10/adult
Total people = 700
Total money = $6,400
First, make two equations.
Let a = # of adults & Let c = # of children.
Let p = total people
1. a+c = 700
2. 10a+7c = 6,400
Then, rearrange the equation to solve for a variable.
c = 700-a
Substitute (700-a) for c, or the # of children in the second equation.
10a+(700-a) = 6400
9a+700 = 6400
9a+700-700 = 6400-700
9a = 5700
9a/9 = 5700/9
a = 633
= # of adults attended700-633

= c =
66
= # of children attended
Answer:
6
Step-by-step explanation:
Because 5.8 is closer to 6 than it is to 5.