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Ivanshal [37]
3 years ago
15

Which of the following shortcuts can be used to say that a triangle is congruent? There is a total of 5 correct answers

Mathematics
1 answer:
artcher [175]3 years ago
8 0

Answer: The give you would use would be SSS, SAS, ASA, AAS, HL

Step-by-step explanation:

The information is also online but never use AAA, or SSA, or the one that spells out an inappropriate word (A)(S)(S)

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48million squared.........
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The base of a solid is the region enclosed by the graphs of y=e^x, y=0, x=0, and x = 1. If each cross-section perpendicular to t
yanalaym [24]

Answer:

A

Step-by-step explanation:

The base of a solid in the region enclosed by the graphs of <em>y</em> = eˣ, <em>y</em> = 0, <em>x </em>= 0, and <em>x</em> = 1. Each cross-section perpendicular to the <em>x</em>-axis is an equilateral triangle. We want to find the volume of the solid.

Please refer to the graph below. We are concerned with the red region.

In order to find the volume, we essentially sum up the area of the figure at each <em>x</em> value. So, we integrate from <em>x </em> = 0 to <em>x </em>= 1.

The area for an equilateral triangle is given by:

\displaystyle A=\frac{\sqrt{3}}{4}s^2

Where <em>s</em> is the side length of the triangle.

Since the triangle lies perpendicular on the region, the side length of the triangle at <em>x</em> is simply <em>y</em>, which is eˣ.

Therefore, our volume is:

\displaystyle V=\int_0^1\frac{\sqrt3}{4}(y)^2\, dx

Substitute:

\displaystyle V=\int_0^1\frac{\sqrt3}{4}(e^x)^2\, dx

Evaluate the integral. Simplify:

\displaystyle V=\frac{\sqrt3}{4}\int_0^1e^{2x}\, dx

Integrate using u-substitution:

\displaystyle V=\frac{\sqrt3}{8}\left(e^{2x}\Big|_0^1\right)

Evaluate:

\displaystyle V=\frac{\sqrt3}{8}\left(e^{2(1)}-e^{2(0)} \right)

Therefore, the volume of the solid is:

\displaystyle V=\frac{\sqrt3}{8}\left(e^2-1\right)

Our answer is A.

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2 years ago
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Answer:

Your answer is b

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Solve the compound inequality<br><br>4 &lt; x - 5 &lt; 12
uysha [10]

4 < x - 5 < 12

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