
The domain is all real numbers as a composition of two linear functions have no restrictions (all linear functions have domain of R)
Answer:
The proportions differ from those reported in the survey.
Step-by-step explanation:
The Chi-square goodness of fit test would be used to determine whether the proportions differ from those reported in the survey.
The hypothesis for the test can be defined as follows:
<em>H</em>₀: The proportions does not differ from those reported in the survey.
<em>Hₐ</em>: The proportions differ from those reported in the survey.
Assume that the significance level of the test is, α = 0.01.
The Chi-square test statistic is given by:

Consider the Excel sheet provided.
The Chi-square test statistic value is 191.32.
The <em>p</em>-value of the test is:

The <em>p</em>-value of the test is very small. The null hypothesis will be rejected at 1% level of significance.
Thus, concluding that the proportions differ from those reported in the survey.
Answer:
=>12-2
=> 10
<em><u>You're Welcome</u></em>
<em><u>Hope this helps you.</u></em>
<h2>
<em><u>Pls</u></em><em><u>, mark it as the brainliest. I need it.</u></em></h2>
Answer:
Step-by-step explanation:
Just squish the two equations into one equation and idk im just typing this because i apparently need a twenty character long answer