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3 years ago

TOT ROLIOS

Mathematics

1 answer:

iren [92.7K]3 years ago

6 0

Answer:

If Mia wants to use 6 cups of rice, she would need to multiply the amount of each ingredient by 3, because the original 2 cups times 3 is the 6 cups she wants to use. So the new amount for the recipe would be this:

6 cups of rice

12 cups of milk

1 cup of sugar

3 handful of raisins

3 cinnamon sticks

When asking how many this will serve, we also multiply by 3 the original amount of people which is 4 to get 12 servings of Arroz con leche

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If a flower bed has the shape of a rectangle 7 yards long and 3 yards wide what is the area in square feet

vichka [17]

I believe it is 189 square feet

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3 years ago

Write a function for the situation. Is the graph continuous or discrete? A movie store sells DVDs for $11 each. What is the cost

Goshia [24]

B: because 11 times N will give you how much your cost would be . Example: 11*2= $22 if you bought 2 cds it would be $22. and its continuous cause youre going up at a constant rate.

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3 years ago

It takes Evan 6 3/4 hours to mow 3 lawns. it takes him 2 1/3 hours to mow Mr. Smiths yard and 1 3/4 hours to mow Ms. Lee's yard.

Ratling [72]

Answer: $2\frac{2}{3}\ hours$

Step-by-step explanation:

Given: The total time taken by Evan to mow the 3 lawns = $6\frac{3}{4}=\frac{27}{4}\ \text{hours}$

Time taken by Evan to mow the first lawn = $2\frac{1}{3}=\frac{7}{3}\ \text{hours}$

Time taken by Evan to mow the second lawn = $1\frac{3}{4}=\frac{7}{4}\ \text{hours}$

Now,Time taken by Evan to mow the third lawn = $\frac{27}{4}-\frac{7}{3}-\frac{7}{4}$

⇒Time taken by Evan to mow the third lawn = $\frac{81-28-21}{12}$

⇒Time taken by Evan to mow the third lawn = $\frac{32}{12}=\frac{8}{3}=2\frac{2}{3}\ hours$

Hence, the time taken by Evan to mow the third lawn = $2\frac{2}{3}\ hours$

7 0

3 years ago

What is the function

Mrrafil [7]

You have the answer correct

4 0

3 years ago

A random sample of 36 students at a community college showed an average age of 25 years. Assume the ages of all students at the

Pavel [41]

Answer:

98% confidence interval for the average age of all students is [24.302 , 25.698]

Step-by-step explanation:

We are given that a random sample of 36 students at a community college showed an average age of 25 years.

Also, assuming that the ages of all students at the college are normally distributed with a standard deviation of 1.8 years.

So, the pivotal quantity for 98% confidence interval for the average age is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample average age = 25 years

$\sigma$ = population standard deviation = 1.8 years

n = sample of students = 36

$\mu$ = population average age

So, 98% confidence interval for the average age, $\mu$ is ;

P(-2.3263 < N(0,1) < 2.3263) = 0.98

P(-2.3263 < $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ < 2.3263) = 0.98

P( $-2.3263 \times {\frac{\sigma}{\sqrt{n} }$ < ${\bar X - \mu}$ < $2.3263 \times {\frac{\sigma}{\sqrt{n} }$ ) = 0.98

P( $\bar X - 2.3263 \times {\frac{\sigma}{\sqrt{n} }$ < $\mu$ < $\bar X +2.3263 \times {\frac{\sigma}{\sqrt{n} }$ ) = 0.98

98% confidence interval for $\mu$ = [ $\bar X - 2.3263 \times {\frac{\sigma}{\sqrt{n} }$ , $\bar X +2.3263 \times {\frac{\sigma}{\sqrt{n} }$ ]

= [ $25 - 2.3263 \times {\frac{1.8}{\sqrt{36} }$ , $25 + 2.3263 \times {\frac{1.8}{\sqrt{36} }$ ]

= [24.302 , 25.698]

Therefore, 98% confidence interval for the average age of all students at this college is [24.302 , 25.698].

8 0

3 years ago