Hey there!
<span>The numerator is the top part of the fraction and the
denominator is the bottom part of the fraction. </span>
For example, in the fraction 
, 1 would be the numerator and 2 would be the denominator.
Thank you!
The slope, y-intercept and the equation of the following graph are as follows:
1(a)
slope : 1
y-intercept: 2
Equation: y = x + 2
(b)
slope : - 1 / 3
y-intercept: - 1
Equation: y = - 1 / 3x - 1
2.
(a)
slope : 3 / 4
y-intercept: 5 / 4
Equation: y = 3 / 4 x + 5 / 4
(b)
slope : - 3 / 2
y-intercept: 1 / 2
Equation: y = - 3 / 2 x + 1 / 2
<h3 />
<h3>Slope intercept equation</h3>
where
m = slope
b = y-intercept
Therefore lets find the slope, y-intercept and equation of the following graph.
1.
(a)
(0, 2)(1, 3)
m = 3 - 2 / 1 - 0 = 1
b = 2
y = x + 2
(b)
(0, -1)(-3, 0)
m = 0 + 1 / -3 - 0 = - 1 / 3
b = -1
y = - 1 / 3x - 1
2.
(a)
(1, 2)(-3, -1)
m = -1 - 2 / -3 - 1 = 3 / 4
2 = 3 / 4 (1) + b
b = 2 - 3 / 4 = 5 / 4
y = 3 / 4 x + 5 / 4
3.
(b)
(-3, 5)(1, -1)
m = - 1 - 5 / 1 + 3 = - 6 / 4 = - 3 / 2
-1 = - 3 /2 (1) + b
b = -1 + 3 / 2 = 1 /2
y = - 3 / 2 x + 1 / 2
learn more on y-intercept here: brainly.com/question/2833377?referrer=searchResults
Answer:
(-1, -2) will be the solution.
Step-by-step explanation:
System of equations has been given as,
y = 3x + 1 ---------(1)
Input-output value table for the given line will be,
x -2 -1 0 1
y -5 -2 1 4
y = -x - 3 ----------(2)
Input-output value table for the given line will be,
x -2 -1 0 1
y -1 -2 -3 -4
By plotting the given coordinates we can draw the straight lines.
And the point of intersection (common point) of these lines will be the solution of the given system of equations.
Hence, (-1, -2) will be the solution.
The answer is 6
i just did the work
Step-by-step explanation:
In order to proof the HA theorem, we consider two triangles and which are right angle triangles. The right angle lies at points and respectively.
We also consider that the hypotenuse are congruent meaning and .
Now we have taken that angle and .
Since and are 90 degrees, so angle B would be congruent to angle E i.e
Hence by Angle, side and angle congruence in both triangles we can write as, .
And this is what the HA thoerem states also
