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sesenic [268]
2 years ago
8

Find the x-intercepts of the parabola with vertex (7,-12) and y-intercept (0,135).

Mathematics
1 answer:
Ira Lisetskai [31]2 years ago
8 0

Answer:

x=9 and x=5

OR

(9,0) and (5,0)

Step-by-step explanation:

<u>Use vertex form to solve for the unknown variable</u>

y=a(x-h)^2+k\\\\135=a(0-7)^2-12\\\\147=a(-7)^2\\\\147=49a\\\\3=a

<u>Use the new equation to find the x-intercepts</u>

<u />y=3(x-7)^2-12\\\\0=3(x-7)^2-12\\\\12=3(x-7)^2\\\\4=(x-7)^2

2=x-7\\9=x

-2=x-7\\5=x

Therefore, the x-intercepts of the parabola are (9,0) and (5,0). Feel free to review the attached graph for more information.

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Answer:

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General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

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Step-by-step explanation:

<u>Step 1: Define</u>

(-10x² + 9) + (8x² - 5x + 7)

<u>Step 2: Simplify</u>

  1. Combine like terms (x²):                                                                                  -2x² + 9 - 5x + 7
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2 years ago
3) Given the box plot below, what is the lower quartile and upper quartile? *
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Answer:

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