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harkovskaia [24]
4 years ago
8

Plz help pretty easy

Mathematics
2 answers:
uysha [10]4 years ago
7 0

Answer:

Hello!!! erz here ^^

Step-by-step explanation:

a and d; b and c (Option 1)

Hope this helps!! :D

cricket20 [7]4 years ago
4 0

a and d b and c that's the answer

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3a=12 is this a literal equation?
Sergio039 [100]

Answer:

Well yes because you do get an answer out that (a=4)

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
the median weekly earnings for american workers in 1990 was $412 and in 1999 it was $549. Calculate the average rate of change b
mina [271]

The rate of change between 1990 and 1999 is 15.22

Step-by-step explanation:

The rate of change in this case is given by change in quantity divided by change in time

So,

Rate\ of\ change = \frac{Increase\ in\ money}{Increase\ in\ time}\\=\frac{549-412}{1999-1990}\\=\frac{137}{9}\\=15.22

Hence,

The rate of change between 1990 and 1999 is 15.22

Keywords: Rate of change, median

Learn more about median at:

  • brainly.com/question/10764770
  • brainly.com/question/1087090

#LearnwithBrainly

5 0
3 years ago
Sin2A + sin5A - sinA÷cos2A + cos5A + COSA=Tan2A​
bezimeni [28]

Answer:

That is the correct answer

Step-by-step explanation:

AND the whole solution I hope it helps to you

7 0
2 years ago
Which is the maximum value of the function y=-3x2 - 15x+9?
blagie [28]

Answer:

B

Step-by-step explanation:

The maximum value of the function is the y- coordinate of the vertex.

Given a parabola in standard form

y = ax² + bx + c ( a ≠ 0 )

Then the x- coordinate of the vertex is

x_{vertex} = - \frac{b}{2a}

y = - 3x² - 15x + 9 ← is in standard form

with a = - 3 and b = - 15, thus

x_{vertex} = - \frac{-15}{-6} = - 2.5

Substitute x = - 2.5 into the equation for y- coordinate of vertex

y = - 3(- 2.5)² - 15(- 2.5) + 9 = - 18.75 + 37.5 + 9 = 27.75 → B

3 0
3 years ago
A motorboat that travels with a speed of 20 km/hour in still water has traveled 20 km against the current and 180 km with the cu
Gala2k [10]
Recall your d = rt.  distance = rate * time.

let's say the speed of the current is "c".

keeping in mind that, when the boat is going against the current, the boat is not really going at 2kmh, but instead at " 20 - c ", because the current is subtracting speed from it.

Likewise when is going with the current, is going at a speed of " 20 + c ".

if the boat took say "t" hours on the way over, on the way back it took the slack from the whole 8 hours and "t", namely it took " 8 - t " hours.

\bf \begin{array}{lccclll}
&\stackrel{km}{distance}&\stackrel{kmh}{rate}&\stackrel{hours}{time}\\
&------&------&------\\
\textit{against the current}&20&20-c&t\\
\textit{with the current}&180&20+c&8-t
\end{array}
\\\\\\
\begin{cases}
20=(20-c)(t)\implies \frac{20}{20-c}=t\\
180=(20+c)(8-\stackrel{\downarrow }{t})\\
--------------\\
180=(20+c)\left( 8- \stackrel{\downarrow }{\frac{20}{20-c}}\right)
\end{cases}
\\\\\\
180=(20+c)\left( \cfrac{(160-8c)-20}{20-c} \right)

\bf 180=(20+c)\left( \cfrac{140-8c}{20-c} \right)\implies 180(20-c)=(20+c)(140-8c)
\\\\\\
3600c-180c=2800-160c+140c-8c^2
\\\\\\
3600c-180c=2800-20c-8c^2
\\\\\\
3600c-180c-2800+20c+8c^2=0\implies 8c^2-160c+800=0
\\\\\\
c^2-20c+100=0\implies (c-10)(c-10)=0\implies \boxed{c=10}
8 0
3 years ago
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