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3 years ago

Plz help pretty easy

Mathematics

2 answers:

uysha [10]3 years ago

7 0

Answer:

Hello!!! erz here ^^

Step-by-step explanation:

a and d; b and c (Option 1)

Hope this helps!! :D

cricket20 [7]3 years ago

4 0

a and d b and c that's the answer

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The side of each of the equilateral triangles in the figure is twice the side of the central regular hexagon. What fraction of t

lana [24]

Answer:

The fraction is 1/4

Step-by-step explanation:

we know that

The area of an equilateral triangle, using the law of sines is equal to

$A=\frac{1}{2}x^{2}sin(60^o)$

$A=\frac{1}{2}x^{2}(\frac{\sqrt{3}}{2})$

$A=x^{2}\frac{\sqrt{3}}{4}$

where

x is the length side of the triangle

In this problem

Let

b ----> the length side of the regular hexagon

2b ---> the length side of the equilateral triangle

step 1

Find the area of the six triangles

Multiply the area of one triangle by 6

$A=6[x^{2}\frac{\sqrt{3}}{4}]$

$A=3x^{2}\frac{\sqrt{3}}{2}$

we have

$x=2b\ units$

substitute

$A=3(2b)^{2}\frac{\sqrt{3}}{2}\\\\A=6b^{2}\sqrt{3}\ units^2$

step 2

Find the area of the regular hexagon

Remember that, a regular hexagon can be divided into 6 equilateral triangles

The area of the regular hexagon is the same that the area of 6 equilateral triangles

$A=3x^{2}\frac{\sqrt{3}}{2}$

we have

$x=b\ in$

substitute

$A=3(b)^{2}\frac{\sqrt{3}}{2}$

step 3

To find out what fraction of the total area of the six triangles is the area of the hexagon, divide the area of the hexagon by the total area of the six triangles

$3(b)^{2}\frac{\sqrt{3}}{2}:6b^{2}\sqrt{3}=\frac{3}{2} :6=\frac{3}{12}=\frac{1}{4}$

3 0

3 years ago

Which equation represents a line which is perpendicular to the line 5x + 2y = 12?

o-na [289]

Answer:

Step-by-step explanation:

Changing to slope-intercept form:

5x + 2y = 12 {subtract 5x from both sides}

2y = -5x + 12 {divide both sides by 2}

y = -⁵/₂ x + 6

y=m₁x+b₁ ⊥ y=m₂x+b₂ ⇔ m₁×m₂ = -1

{Two lines are perpendicular if the product of theirs slopes is equal -1}

y =-⁵/₂ x + 1 ⇒ m₁ = -⁵/₂

-⁵/₂× m₂ = -1 ⇒ m₂ = ²/₅

So, any line perpendicular to 5x + 2y = 12 must have slope m =²/₅

7 0

2 years ago

Select all the expressions whose value is larger than 100.

scZoUnD [109]

Answer:

120% of 100. 20% of 800. 500% of 400. 1% of 1,000

Hope this helps :)

4 0

3 years ago

I’m supposed to find the slope intercept form. The x intercept is (2,0) and the y intercept is (0,6). I keep getting 6/2. But, t

Lilit [14]

$\bf \stackrel{x-intercept}{(\stackrel{x_1}{2}~,~\stackrel{y_1}{0})}\qquad \stackrel{y-intercept}{(\stackrel{x_2}{0}~,~\stackrel{y_2}{6})} \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{6-0}{0-2}\implies \cfrac{6}{-2}\implies -3 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-0=-3(x-2)\implies y=-3x+6$

5 0

3 years ago

How to solve x=6y-11 and 3x-2y=-1 by substitution

vagabundo [1.1K]

Substitute x into the second equation:
3(6y-11)-2y=-1
18y-33-2y=-1
16y=32
y=2
Then put the y value into the first equation to get x:
x=6(2)-11
x=1
There you go!

Please mark brainliest

7 0

3 years ago