X
+
6
−
5
=
8
−
2
+
6
−
5
=
8
−
2
Solve
1
Subtract the numbers
x
+
6
−
5
=
8
−
2
+
6
−
5
=
8
−
2
x
+
1
=
8
−
2
+
1
=
8
−
2
2
Subtract the numbers
x
+
1
=
8
−
2
+
1
=
8
−
2
x
+
1
=
6
+
1
=
6
3
Subtract
1
1
from both sides
x
+
1
=
6
+
1
=
6
x
+
1
−
1
=
6
−
1
+
1
−
1
=
6
−
1
4
Simplify
Subtract the numbers
Subtract the numbers
x
=
5
=
5
x = 1/120
i did not see the comment about the 1/5 until now
hope this helps
Answer:
The frequency of the note a perfect fifth below C4 is;
B- 174.42 Hz
Step-by-step explanation:
Here we note that to get the "perfect fifth" of a musical note we have to play a not that is either 1.5 above or 1.5 below the note to which we reference. Therefore to get the frequency of the note a perfect fifth below C4 which is about 261.63 Hz, we have
1.5 × Frequency of note Y = Frequency of C4
1.5 × Y = 261.63
Therefore, Y = 261.63/1.5 = 174.42 Hz.
83 + 94 + 79 + 97 + 96 + 87 = 536.
536 ÷ 6 = 89.333333...
So, Lamonts' average is under 90.
