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alexira [117]
3 years ago
15

Find the distance between (3, −7) and (4, 1)

Mathematics
1 answer:
m_a_m_a [10]3 years ago
7 0

Answer:sqrt65

Step-by-step explanation:

Distance formula d = \sqrt{(x_2 - x_1)^2 + (y_2-y_1)^2}

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Consider the pair of angles given in the first column. Use the following answers to identify each angle.
Vikki [24]

<4 and <2  corresponding angles

<6 and <3  alternate interior angles

<4 and <5 alternate exterior angles

<6 and <7 interior angles on the same side of transversal

3 0
3 years ago
Which of the following statements does not describe the structure of an atom?
blagie [28]

Answer:

B) Inside the nucleus of an atom are protons and electrons.

Explanation:

Inside the nucleus of an atom are protons and neutrons. Electrons orbit (kind of?) away from the nucleus.

8 0
2 years ago
Alexia took out a 12-year loan for $72000 to renovate her home. If her monthly payments are $680, what is the interest rate?
mart [117]

Answer:

intrest equation

I/PT = R

$680 / $72,000 x 12 years = R

$680 / $864,000 = R

7.8703 = R

or rounded 8%

Step-by-step explanation:

3 0
3 years ago
Which lines are parallel?
Reptile [31]

Answer:

Lines 'p' and 'q' are parallel I believe!

Step-by-step explanation:

They are the only two lines relating to angles 8 and 11 of the three listed pairs.

3 0
3 years ago
Read 2 more answers
A polynomial has a leading coefficient of 1 and the
Hoochie [10]

Answer:

(A)[x-(2+i)][x-(2-i)][x-\sqrt{2}][x+\sqrt{2}]

Step-by-step explanation:

A polynomial has a leading coefficient of 1 and the  following factors with multiplicity 1:

x-(2+i)\\x-\sqrt{2}

We apply the following to find the factored form of the polynomial.

  • If a complex number is a root of a polynomial with real coefficients, its complex conjugate is also a root of that polynomial.
  • If the polynomial has an irrational root a+\sqrt{b}, where a and b are rational and b is not a perfect square, then it has also a conjugate root a-\sqrt{b}.

\text{Complex conjugate of }x-(2+i)=x-(2-i)\\\\\text{Complex conjugate of }x-\sqrt{2}=x+\sqrt{2}

Therefore, the factored form of the polynomial is:

[x-(2+i)][x-(2-i)][x-\sqrt{2}][x+\sqrt{2}]

7 0
3 years ago
Read 2 more answers
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