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nikklg [1K]
2 years ago
5

Louie made 8.1 liters of fruit punch using only grape juice and carbonated water. He used 4.2 liters of grape juice. The equatio

n 4.2 + c = 8.1 can be used to represent this situation, where c is the number of liters of carbonated water used. How many liters of carbonated water did Louie use?
Mathematics
1 answer:
Dmitriy789 [7]2 years ago
7 0

Given:

The equation is:

4.2+c=8.1

Where c is the number of liters of carbonated water used.

To find:

How many liters of carbonated water did Louie use?

Solution:

We have,

4.2+c=8.1

We need to solve this equation for c to find the number of liters of carbonated water used by Louie.

Subtracting 4.2 from both sides, we get

4.2+c-4.2=8.1-4.2

c=3.9

Therefore, Louie used 3.9 liters of carbonated water.

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natta225 [31]
Perimeter of a rectangle = 2L + 2W

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W = 8.5

we plug those into the perimeter equation and get
2L + 2(8.5) = 39

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2L = 22

divide both sides by 2
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2 years ago
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An easy trick to help remember when it is a multiple of 10 is that you do the numbers that aren't zero (2) times 10 and the exponent is how ever many zeros there are after the other numbers (3).
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simplified answer

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From the table below, determine whether the data shows an exponential function. Explain why or why not.
Ierofanga [76]
X        Δx                                   y             Δy

3                                               1          

1        1 - 3 = - 2                        2             2 - 1 = 1

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-3        -3 - (-1) = -2                  4               4 - 3 = 1


So, as you see y in increasing in regular constant intervals, when x also increases in regular constant intervals. => Δy / Δx = constant.

That is the result of a linear function, not an exponential one.

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8 0
3 years ago
The volume of a rectangular box with a square base remains constant at 500 cm3 as the area of the base increases at a rate of 6
Andre45 [30]

Answer:

the rate at which the height of the box is decreasing is -0.0593 cm/s

Step-by-step explanation:

Given the data in the question;

Constant Volume of a rectangular box with a square base = 500 cm³

area of the base increases at a rate of 6 cm²/sec

so change in the area of the base with respect to time dA/dt = 6 cm²/sec

each side of the base is 15 cm long

so Area of the base = 15 cm × 15 cm = 225 cm²

the rate at which the height of the box is decreasing = ?

Now,

V = Ah

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⇒ dh/dt = -hdA/dt / A

we substitute

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Therefore, the rate at which the height of the box is decreasing is -0.0593 cm/s

7 0
2 years ago
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