Answer:
Hello! A function is easily identified when an x value does not have more than 1 y value. a y value can have as many x values to infinity, but x can only have one y.
Example...
x y
3 5
4 5
1 2
Answer:
Options: A, B, and C correctly solve for x.
Step-by-step explanation:
A).
= 
Multiplying both sides by 2 gives;
5x = 15
x = 15 ÷ 5 = 3
∴ This option correctly solve for x.
B).
x +
= 7
x = 7 -
= 
∴ This option correctly solve for x.
C).
x + 3 = 
x = 
But the option give x as 5/6 hence this option does not correctly solve for x.
D).
5x = 11/2
x = 11/2 ÷ 5 = 11/2 × 1/5 = 11/10
But the option gives x as 10/11 so it does not correctly solve for x.
Answer:
-15x^2 +8x -1
Step-by-step explanation:
(3x – 1)(-5x + 1)=
3x(-5x) + 3x(1) - 1(-5x) -1 =
-15x^2 +3x +5x -1 =
-15x^2 +8x -1
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