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Gnesinka [82]
3 years ago
7

2 1/2 lb = ____________

Mathematics
2 answers:
Levart [38]3 years ago
8 0
Ok so 2 1/2 lb = something and I don’t know what is that thing. For example, 2 1/2 = ounces? Like that. I don’t even know what you want for answer.
aev [14]3 years ago
7 0
I don’t even have any friends who are not
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Which graph below does not represent a function?
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the first one

Step-by-step explanation:

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2 years ago
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Factor both quadratic expressions. (x 4 + 5x 2 - 36)(2x 2 + 9x - 5) = 0
Sonbull [250]

So focusing on x^4 + 5x^2 - 36, we will be completing the square. Firstly, what two terms have a product of -36x^4 and a sum of 5x^2? That would be 9x^2 and -4x^2. Replace 5x^2 with 9x^2 - 4x^2: x^4+9x^2-4x^2-36

Next, factor x^4 + 9x^2 and -4x^2 - 36 separately. Make sure that they have the same quantity inside of the parentheses: x^2(x^2+9)-4(x^2+9)

Now you can rewrite this as (x^2-4)(x^2+9) , however this is not completely factored. With (x^2 - 4), we are using the difference of squares, which is a^2-b^2=(a+b)(a-b) . Applying that here, we have (x+2)(x-2)(x^2+9) . x^4 + 5x^2 - 36 is completely factored.

Next, focusing now on 2x^2 + 9x - 5, we will also be completing the square. What two terms have a product of -10x^2 and a sum of 9x? That would be 10x and -x. Replace 9x with 10x - x: 2x^2+10x-x-5

Next, factor 2x^2 + 10x and -x - 5 separately. Make sure that they have the same quantity on the inside: 2x(x+5)-1(x+5)

Now you can rewrite the equation as (2x-1)(x+5) . 2x^2 + 9x - 5 is completely factored.

<h3><u>Putting it all together, your factored expression is (x+2)(x-2)(x^2+9)(2x-1)(x+5)=0</u></h3>
5 0
3 years ago
The H.C.F. of 3150 and a number is 42. Which of the following can be the number?
Eduardwww [97]

2^{2} *3^{2} *5=4*9*5=4*45=180\\2^{2} *3^{2} *5^{2} =4*9*25=36*25=900\\2^{2} *3*7=4*3*7=4*21=84\\2^{2} *3^{2} *7=4*9*7=36*7=252\\

raspunsul, e, B, 900

5 0
2 years ago
The area of a sector with a central angle of 30' is 150'. Determine the approximate length of the diameter.
ioda

Answer:

It looks different. Can you provide some formulae based on it. I may help you out in the comment section!

4 0
2 years ago
If sinA =3/5 and A+B =90 find cosB
-Dominant- [34]

A+B=90^o\to B=90^o-A\\\\\cos B=\cos(90^o-A)=\cos90^o\cos A+\sin90^o\sin A\\\\=\cos A+1\cdot\dfrac{3}{5}=0+\dfrac{3}{5}=\dfrac{3}{5}\\\\\boxed{\cos B=\dfrac{3}{5}}

Used:\\\\\cos(x+y)=\cos x\cos y+\sin x\sin y\\\\\cos90^o=0,\ sin90^o=1

Other method:

Look at the picture.

\sin\theta=\dfrac{opposite}{hypotenuse}\\\\\sin A=\dfrac{3}{5}\to opposite=3\ and\ hypotenuse=5

\cos\theta=\dfrac{adjacent}{hypotenuse}\\\\adjacent=3\ and\ hypotenuse=5\to\cos B=\dfrac{3}{5}

8 0
3 years ago
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