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3 years ago

Will give Brainliest! if right!

Mathematics

2 answers:

melisa1 [442]3 years ago

8 0

The correct answer is B because i did this im a 100%

liraira [26]3 years ago

3 0

A.) Not biased, they are surveying all of the passengers on this particular flight to get a general idea of the rating.

Also, this shouldn't be under the mathematics category.

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Plzzzz plzzzz help me the word has to have the root man

riadik2000 [5.3K]

I don't know the root you are talking about but i would say "we might say that they are bulk"

5 0

3 years ago

He short sides of a rectangle are 2 inches. The long sides of the same rectangle are three less than an unknown number of inches

goldenfox [79]

The sum of two adjacent sides is 11 inches, so the long sides are 9 inches. The "unknown number" must be 12.

7 0

3 years ago

eric has a riddle: " i am thinking of a fraction that is equivalent to 2/5 and the numerator is 18 less than the denominator." w

dezoksy [38]

Answer:

12/30

Step-by-step explanation:

So we know that the denominator-numerator=18

And we also know that it's equal to 4/10 or 2/5.

Soooooooooooooo the most easiest is just to trial and error: 12/30

But I don't really know the more complex formula...

5 0

3 years ago

There are two flavors of ice cream; strawberry and chocolate. the amount of strawberry ice cream is in the shape of a sphere. th

amid [387]

The complete question is
There are two flavors of ice cream; strawberry and chocolate. the amount of strawberry ice cream is in the shape of a sphere. the amount of chocolate ice cream fills the rest of the cone. the dimensions of the sphere is 6cm and the cone is 12cm.

the figure is not drawn to scale

A. what is the volume, in cubic centimeters of the right circular cone ?show or explain how you got your answer.
B. the amount of strawberry ice cream is in the shape of a sphere. what is the volume in cubic centimeters of the strawberry ice cream?
C. what is the total volume in cubic centimeters of all the ice creams?
D.the amount of chocolate ice cream fills the rest of the cone. what is the volume in cubic centimeters of the chocolate ice cream?

we know that
the height of the cone is 12 cm
the diameter of a cone is 6 cm

Part A) what is the volume, in cubic centimeters of the right circular cone? show or explain how you got your answer.

we know that
the volume of a cone=(1/3)*pi*r²*h
r=6/2----> 3 cm
h=12 cm
The volume of a cone=(1/3)*pi*3²*12------> 36*pi cm³-------> 113.04 cm³

the answer part A) is 36*pi cm³ (113.04 cm³)

Part B) the amount of strawberry ice cream is in the shape of a sphere. what is the volume in cubic centimeters of the strawberry ice cream?
volume of a sphere=(4/3)*pi*r³
r=3 cm
volume of a sphere=(4/3)*pi*3³-----> 36*pi cm³------> 113.04 cm³

the answer part B) is 36*pi cm³ (113.04 cm³)

Part C) what is the total volume in cubic centimeters of all the ice creams?
volume of the cone+volume of a hemisphere

36*pi+18*pi-----> 54*pi cm³-------> 169.56 cm³

the answer Part C) is 54*pi cm³ (169.56 cm³)

Part D) .the amount of chocolate ice cream fills the rest of the cone. what is the volume in cubic centimeters of the chocolate ice cream?
volume of a cone-volume of a hemisphere
36*pi-18*pi-----> 18*pi cm³-----> 56.52 cm³

the answer Part D) is 18*pi cm³ (56.52 cm³)

5 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Cleft%20%5C%7B%20%7B%7Bx%2By%3D1%7D%20%5Catop%20%7Bx-2y%3D4%7D%7D%20%5Cright.%20%5C%5C%5Clef

brilliants [131]

Answer:

(a) x=2, y=-1

(b) x=2, y=2

(c) $\displaystyle x=\frac{5}{2}, y=\frac{5}{4}$

(d) x=-2, y=-7

Step-by-step explanation:

Cramer's Rule

It's a predetermined sequence of steps to solve a system of equations. It's a preferred technique to be implemented in automatic digital solutions because it's easy to structure and generalize.

It uses the concept of determinants, as explained below. Suppose we have a 2x2 system of equations like:

$\displaystyle \left \{ {{ax+by=p} \atop {cx+dy=q}} \right.$

We call the determinant of the system

$\Delta=\begin{vmatrix}a &b \\c &d \end{vmatrix}$

We also define:

$\Delta_x=\begin{vmatrix}p &b \\q &d \end{vmatrix}$

And

$\Delta_y=\begin{vmatrix}a &p \\c &q \end{vmatrix}$

The solution for x and y is

$\displaystyle x=\frac{\Delta_x}{\Delta}$

$\displaystyle y=\frac{\Delta_y}{\Delta}$

(a) The system to solve is

$\displaystyle \left \{ {{x+y=1} \atop {x-2y=4}} \right.$

Calculating:

$\Delta=\begin{vmatrix}1 &1 \\1 &-2 \end{vmatrix}=-2-1=-3$

$\Delta_x=\begin{vmatrix}1 &1 \\4 &-2 \end{vmatrix}=-2-4=-6$

$\Delta_y=\begin{vmatrix}1 &1 \\1 &4 \end{vmatrix}=4-3=3$

$\displaystyle x=\frac{\Delta_x}{\Delta}=\frac{-6}{-3}=2$

$\displaystyle y=\frac{\Delta_y}{\Delta}=\frac{3}{-3}=-1$

The solution is x=2, y=-1

(b) The system to solve is

$\displaystyle \left \{ {{4x-y=6} \atop {x-y=0}} \right.$

Calculating:

$\Delta=\begin{vmatrix}4 &-1 \\1 &-1 \end{vmatrix}=-4+1=-3$

$\Delta_x=\begin{vmatrix}6 &-1 \\0 &-1 \end{vmatrix}=-6-0=-6$

$\Delta_y=\begin{vmatrix}4 &6 \\1 &0 \end{vmatrix}=0-6=-6$

$\displaystyle x=\frac{\Delta_x}{\Delta}=\frac{-6}{-3}=2$

$\displaystyle y=\frac{\Delta_y}{\Delta}=\frac{-6}{-3}=2$

The solution is x=2, y=2

$\displaystyle \left \{ {{-x+2y=0} \atop {x+2y=5}} \right.$

Calculating:

$\Delta=\begin{vmatrix}-1 &2 \\1 &2 \end{vmatrix}=-2-2=-4$

$\Delta_x=\begin{vmatrix}0 &2 \\5 &2 \end{vmatrix}=0-10=-10$

$\Delta_y=\begin{vmatrix}-1 &0 \\1 &5 \end{vmatrix}=-5-0=-5$

$\displaystyle x=\frac{\Delta_x}{\Delta}=\frac{-10}{-4}=\frac{5}{2}$

$\displaystyle y=\frac{\Delta_y}{\Delta}=\frac{-5}{-4}=\frac{5}{4}$

The solution is

$\displaystyle x=\frac{5}{2}, y=\frac{5}{4}$

(d) The system to solve is

$\displaystyle \left \{ {{6x-y=-5} \atop {4x-2y=6}} \right.$

Calculating:

$\Delta=\begin{vmatrix}6 &-1 \\4 &-2 \end{vmatrix}=-12+4=-8$

$\Delta_x=\begin{vmatrix}-5 &-1 \\6 &-2 \end{vmatrix}=10+6=16$

$\Delta_y=\begin{vmatrix}6 &-5 \\4 &6 \end{vmatrix}=36+20=56$

$\displaystyle x=\frac{\Delta_x}{\Delta}=\frac{16}{-8}=-2$

$\displaystyle y=\frac{\Delta_y}{\Delta}=\frac{56}{-8}=-7$

The solution is x=-2, y=-7

4 0

3 years ago