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bearhunter [10]

3 years ago

11

Can somebody plz help and explain this

2 answers:

Yanka [14]3 years ago

7 0

Answer:

C is the answer

Step-by-step explanation:

Please mark brainliest

andreev551 [17]3 years ago

3 0

The correct answer is C

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What is the value of cos(infinity)?

Monica [59]

The problem ask to find the value of the cos(infinity) and the best answer, base on my further calculation and formulation that came up to a solution that leads me to an answer that the cos(infinity) is undefined but it has a range of (-1,1). I hope you are satisfied with my answer and feel free to ask for more

3 0

2 years ago

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Which term best describes the expression 3x2y4 + 5x + 1?

notka56 [123]

Answer:

Trinomial.

Step-by-step explanation:

Note how much terms there are in the given expressions:

Term 1: $3x^{2}y^{4}\$

Term 2: $5x$

Term 3: $1$

Note each meaning of the terms:

Monomial: Having only one term.

Binomial: Having two terms.

Trinomial: Having three terms.

Polynomial: Typically used to describe expressions with 4 or more terms.

In this case, there are only 3 terms, and so your answer is Trinomial.

~

5 0

1 year ago

If 180° < α < 270°, cos⁡ α = −817, 270° < β < 360°, and sin⁡ β = −45, what is cos⁡ (α + β)?

eduard

Answer:

$cos(\alpha+\beta)=-\frac{84}{85}$

Step-by-step explanation:

we know that

$cos(\alpha+\beta)=cos(\alpha)*cos(\beta)-sin(\alpha)*sin(\beta)$

Remember the identity

$cos^{2} (x)+sin^2(x)=1$

step 1

Find the value of $sin(\alpha)$

we have that

The angle alpha lie on the III Quadrant

so

The values of sine and cosine are negative

$cos(\alpha)=-\frac{8}{17}$

Find the value of sine

$cos^{2} (\alpha)+sin^2(\alpha)=1$

substitute

$(-\frac{8}{17})^{2}+sin^2(\alpha)=1$

$sin^2(\alpha)=1-\frac{64}{289}$

$sin^2(\alpha)=\frac{225}{289}$

$sin(\alpha)=-\frac{15}{17}$

step 2

Find the value of $cos(\beta)$

we have that

The angle beta lie on the IV Quadrant

so

The value of the cosine is positive and the value of the sine is negative

$sin(\beta)=-\frac{4}{5}$

Find the value of cosine

$cos^{2} (\beta)+sin^2(\beta)=1$

substitute

$(-\frac{4}{5})^{2}+cos^2(\beta)=1$

$cos^2(\beta)=1-\frac{16}{25}$

$cos^2(\beta)=\frac{9}{25}$

$cos(\beta)=\frac{3}{5}$

step 3

Find cos⁡ (α + β)

$cos(\alpha+\beta)=cos(\alpha)*cos(\beta)-sin(\alpha)*sin(\beta)$

we have

$cos(\alpha)=-\frac{8}{17}$

$sin(\alpha)=-\frac{15}{17}$

$sin(\beta)=-\frac{4}{5}$

$cos(\beta)=\frac{3}{5}$

substitute

$cos(\alpha+\beta)=-\frac{8}{17}*\frac{3}{5}-(-\frac{15}{17})*(-\frac{4}{5})$

$cos(\alpha+\beta)=-\frac{24}{85}-\frac{60}{85}$

$cos(\alpha+\beta)=-\frac{84}{85}$

4 0

3 years ago

Brainliest if your correct

loris [4]

Answer:

it would be the last option

Step-by-step explanation:

4 0

2 years ago

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The blue figure is a dilation of the black figure. the labeled point is the center of dilation. tell whether the dilation is an

Varvara68 [4.7K]

Answer:

Step-by-step explanation:

um

8 0

2 years ago