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2 years ago

If p(a) = 0.50, p(b) = 0.60, and p(a intersection

1 answer:

5 0

Use the identity P(A ∪ B) = P(A)+P(B)-P(A ∩ B)

P(A)=0.50
P(B)=0.60
P(A ∪ B) = 0.30
=>
P(A ∪ B) = P(A)+P(B)-P(A ∩ B)
=(0.50+0.60)-0.30
=0.80

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FOR 47 POINTS PLEASE HELP

Julli [10]

Answer:

UV=25 units

Step-by-step explanation:

we know that

UW=UV+VW -----> by addition segment postulate

substitute the given values

4x+10=5x+5

solve for x

5x-4x=10-5

x=5

Find the value of UV

UV=5x

substitute the value of x

UV=5(5)=25 units

3 0

2 years ago

If h(x)=5x-3 find h(-4)

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5(-4)-3
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2 years ago

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the height of mont blanc is 4810 m correct to the nearest 10 meters. what is its least possible height

SSSSS [86.1K]

Answer:

4800m

Step-by-step explanation:

"correct to the nearest 10 meters" means that the height can vary ± 10 meters.

4810 m ± 10 m = 4800 to 4820

4800 is the least possible height.

7 0

3 years ago

ON YOUR OWN:

qwelly [4]

Answer:

125 defective jeans

Step-by-step explanation:

We are told that;

During inspections, 5 defective pairs of jeans are found in a shipment of 200 pairs of jeans .

We are supposed to determine the number of defective jeans in a shipment of 5000 pairs, if the trend continues.

Therefore;

5 defective = 200 pairs

What about in 5000 pairs?

Number of defective pairs = (5000 × 5 ) ÷ 200

= 125 defective pairs

Thus, in a shipment of 5000 pairs of jeans there will be 125 defective pairs

6 0

3 years ago

Beaker A contains 1 liter which is 30 percent oil and the rest is vinegar, thoroughly mixed up. Beaker B contains 2 liters which

alekssr [168]

Answer:

1.25 liters of oil

Step-by-step explanation:

Volume in Beaker A = 1 L

Volume of Oil in Beaker A = 1*0.3 = 0.3 L

Volume of Vinegar in Beaker A = 1*0.7 = 0.7 L

Volume in Beaker B = 2 L

Volume of Oil in Beaker B = 2*0.4 = 0.8 L

Volume of Vinegar in Beaker B = 1*0.6 = 1.2 L

If half of the contents of B are poured into A and assuming a homogeneous mixture, the new volumes of oil (Voa) and vinegar (Vva) in beaker A are:

$V_{oa} = 0.3+\frac{0.8}{2} \\V_{oa} = 0.7 \\V_{va} = 0.7+\frac{1.2}{2} \\V_{va} = 1.3$

The amount of oil needed to be added to beaker A in order to produce a mixture which is 60 percent oil (Vomix) is given by:

$0.6*V_{total} = V_{oa} +V_{omix}\\0.6*(V_{va}+V_{oa} +V_{omix}) = V_{oa} +V_{omix}\\0.6*(1.3+0.7+V_{omix})=0.7+V_{omix}\\V_{omix}=\frac{0.5}{0.4} \\V_{omix}=1.25 \ L$

1.25 liters of oil are needed.

6 0

3 years ago