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4 years ago

What is the area of this polygon?

Mathematics

2 answers:

IrinaK [193]4 years ago

8 0

Answer:

The area of this polygon is 39

Step-by-step explanation:

Ivahew [28]4 years ago

4 0

The above polygon is a pentagon
The polygon has a rectangle and a triangle
Area of triangle FSCW
= Length × width
= 9 × 2
= 18 square units
area of triangle FNS
= 1/2 × base× height
= 1/2 × 9 × 6
= 27 square units
Therefore the area of the polygon is
= 27 + 18
= 45 square units

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Mary has to spend $18000 on expenses each year.if that amount of money 40% of her salary then how much does Mary make working as

Naddik [55]

Answer:

40% × ? = 18,000

? =

18,000 ÷ 40% =

18,000 ÷ (40 ÷ 100) =

(100 × 18,000) ÷ 40 =

1,800,000 ÷ 40 =

45,000

4 0

4 years ago

What is the explicit formula for this sequence?

Zarrin [17]

Step-by-step explanation:

The above sequence is a geometric sequence

For an nth term in a geometric sequence

$a(n) = a ({r})^{n - 1}$

where

n is the number of terms

a is the first term

r is the common ratio

From the question

a = 5

r = 10/5 = 2

Therefore the explicit formula for this sequence is

$a(n) = 5( {2})^{n - 1}$

Hope this helps you

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4 years ago

Law of radicals

andrey2020 [161]

Answer:

1) $\sqrt{x^7}=x^{\frac{7}{2}$

2) $\sqrt[3]{y^5}=y^{\frac{5}{3}$

3) $\sqrt[5]{a^{12}}=a^{\frac{12}{5} }$

4) $\sqrt[4]{z^{9}}=z^\frac{9}{4}$

Step-by-step explanation:

1) $\sqrt{x^7}$

We know that $\sqrt{x}=x^{\frac{1}{2}$

So, $\sqrt{x^7}=x^{\frac{7}{2}$

2) $\sqrt[3]{y^5}$

We know that $\sqrt[3]{x}=x^{\frac{1}{3}$

So, $\sqrt[3]{y^5}=y^{\frac{5}{3}$

3) $\sqrt[5]{a^{12}}$

We know that $\sqrt[5]{x}=x^{\frac{1}{5}$

So, $\sqrt[5]{a^{12}}=a^{\frac{12}{5} }$

4) $\sqrt[4]{z^{9}}$

We know that $\sqrt[4]{x}=x^{\frac{1}{4}$

So, $\sqrt[4]{z^{9}}=z^\frac{9}{4}$

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4 years ago

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viktelen [127]

We can calculate the slope by using the slope formula!

$\frac{y_2 - y_1}{x_2 - x_1}$

We now just plug in our values which are:

$\frac{8+1}{3-2}=9$

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3 years ago