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3 years ago

The speed of the international space station is 27,576 kilometres per hour.

1 answer:

7 0

(27576km/hr)(24hr/day)(orbits/42600km)=orbits/day=15.53

So the station makes 15 FULL orbits per day

(27576km/h)(1000m/km)(h/3600s)=7660m/s

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in right triangle ABC, angle C is a right angle, AB is 25 units long, and BC is 24 units long. What is the lenght of AC?

ycow [4]

Answer:

7 units long

Step-by-step explanation:

We are given a right triangle ABC

AB = 25 units
BC = 24 units

We are required to determine the length of AC

We are going to use the Pythagoras theorem;
According to the theorem, if a and b are the legs of a right triangle and c is the hypotenuse, then;

a² + b² = c²

In this case;

AB is the hypotenuse and BC is one of the legs of the triangle;

Therefore;

AB² = BC²+AC²

Rearranging the formula;

AC² = AB² - BC²

= 25² - 24²

= 625 - 576

= 49

AC = √49

= 7

Thus, AC is 7 units long

6 0

3 years ago

4 friends share 3 oranges equally. How much does each friend get?

saveliy_v [14]

3 oranges / 4 friends = 3/4 orange for each of them, or 0.75 orange each

(You can check the answer by saying, if each of them get 3/4 of an orange, then multiplying that by the 4 friends should give me the 3 oranges. 3/4 x 4 = 3, so it's correct).

6 0

3 years ago

Read 2 more answers

A rectangle has its base on the x axis and its upper two vertices on the parabola y = 9 − x2. (a) Draw a graph of this problem.

gtnhenbr [62]

Answer:

(a) see attached
(b) width: 2x; height: y = 9-x²
(c) A=2x(9-x²) . . . 0 ≤ x ≤ 3
(d) dA/dx = -6x² +18; x=±√3
(e) 12√3 units²

Step-by-step explanation:

(a) The attachment shows the graph of the parabola in blue. It also shows an inscribed rectangle in black.

(b) The upper right point of the rectangle is shown in the attachment as (x, y). The dimension y is the height of the rectangle. The x-dimension is half the width of the rectangle, which is symmetrical about the y-axis. Hence the width is 2x.

(c) As with any rectangle, the area is the product of length and width:

... A = (2x)(9 -x²) . . . . . the attachment shows a graph of this

... A = -2x³ +18x . . . . . expanded form suitable for differentiation

A suitable domain for A is where both x and A are non-negative: 0 ≤ x ≤ 3.

(d) The derivative of A with respect to x is ...

... A' = -6x² +18

This is defined everywhere, so the critical values will be where A' = 0.

... 0 = -6x² +18

... 3 = x² . . . . . . . divide by -6, add 3

... √3 = x . . . . . . . -√3 is also a solution, but is not in the domain of A

(e) The rectangle will have its largest area where x=√3. That area is ...

... A = 2x(9 -x²) = 2√3(9 -(√3)²) = 2√3(6)

... A = 12√3 . . . . square units . . . . ≈ 20.785 units²

7 0

3 years ago

In humans, coral is sometimes used to replace sections of

Tom [10]

Coral is sometimes used to replace human bone

5 0

3 years ago

According to the American Lung Association, 7% of the population has lung disease. Of those having lung disease, 90% are smokers

postnew [5]

Answer:

Probability that a smoker has lung disease = 0.2132

Step-by-step explanation:

Let L = event that % of population having lung disease, P(L) = 0.07

So,% of population not having lung disease, P(L') = 1 - P(L) = 1 - 0.07 = 0.93

S = event that person is smoker

% of population that are smokers given they are having lung disease, P(S/L) = 0.90

% of population that are smokers given they are not having lung disease, P(S/L') = 0.25

We know that, conditional probability formula is given by;

P(S/L) = $\frac{P(S\bigcap L)}{P(L)}$

$P(S\bigcap L)$ = P(S/L) * P(L)

= 0.90 * 0.07 = 0.063

So, $P(S\bigcap L)$ = 0.063 .

Now, probability that a smoker has lung disease is given by = P(L/S)

P(L/S) = $\frac{P(S\bigcap L)}{P(S)}$

P(S) = P(S/L) * P(L) + P(S/L') * P(L')

= 0.90 * 0.07 + 0.25 * 0.93 = 0.2955

Therefore, P(L/S) = $\frac{0.063}{0.2955}$ = 0.2132

Hence, probability that a smoker has lung disease is 0.2132 .

7 0

4 years ago