The speed of the international space station is 27,576 kilometres per hour.

1 answer:

7 0

(27576km/hr)(24hr/day)(orbits/42600km)=orbits/day=15.53

So the station makes 15 FULL orbits per day

(27576km/h)(1000m/km)(h/3600s)=7660m/s

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In ΔUVW, w = 3 inches, ∠W=23° and ∠U=73°. Find the length of u, to the nearest 10th of an inch.

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<h2>7.4inches</h2>

Step-by-step explanation:

Check the attachment for the diagram. Sine rule will be used to get the unknown side of the triangle.

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Given w = 3 in, ∠W=23° and ∠U=73°, on substituting into the equation above to get u we have;

$\frac{u}{sin73^{0} } = \frac{3}{sin23^{0} }\\usin23^{0} = 3sin73^{0}\\u = \frac{3sin73^{0} }{sin23^{0} }\\u = \frac{2.87}{0.39} \\u = 7.358\\u = 7.4in$