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Daniel [21]
3 years ago
11

Scores on a certain IQ test are knownto have a mean of 100. A random sample of 43 students attend a series of coaching classes b

efore taking the test. Let \small \mu be the population mean IQ score that would occur if every student took the coaching classes.The classes are successful if \small \mu > 100 . A test is made of the hypothesis \small H_{0}:\mu = 100 versus \small H_{1}:\mu > 100
Consider three possible conclusions :
(i) The classes are successful
(ii) The classes are not successful
(iii) The classes might not be successful.
Part 1
Assume that the classes are successsful but the conclusion is reached that the classes might not be successful. Which type of error is this?
Part 2
Assume that the classes are not successful. It is possible to make a type II error? Explain.
_______(Yes, No) , a type II error _____(is, is not) possible. The classes are not successful when the null hypothesis is______(true, false).
Mathematics
1 answer:
NeX [460]3 years ago
6 0

Answer:

Part 1

Type II error

Part 2

No ; is not ; true

Step-by-step explanation:

Data provided in the question

Mean = 100

The Random sample is taken = 43 students

Based on the given information, the conclusion is as follows

Part 1

Since it is mentioned that the classes are successful which is same treated as a null rejection and at the same time it also accepts the alternate hypothesis

Based on this, it is a failure to deny or reject the false null that represents type II error

Part 2

And if the classes are not successful so we can make successful by making type I error and at the same time type II error is not possible

Therefore no type II error is not possible and when the null hypothesis is true the classes are not successful

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Step by step please and thank you.
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Answer:

  the probability is 2/9

Step-by-step explanation:

Assuming the coins are randomly selected, the probability of pulling a dime first is the number of dimes (4) divided by the total number of coins (10).

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Then, having drawn a dime, there are 9 coins left, of which 5 are nickels. The probability of randomly choosing a nickel is 5/9.

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_____

<em>Alternate solution</em>

You can go at this another way. You can list all the pairs of coins that can be drawn. There are 90 of them: 10 first coins and, for each of those, 9 coins that can be chosen second. Of these 90 possibilities, there are 4 dimes that can be chosen first, and 5 nickels that can be chosen second, for a total of 20 possible dime-nickel choices out of the 90 total possible outcomes.

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A geometric sequence is a sequence in which there is a common ratio between any two consecutive terms. In this case if X:Y:Z are in the ratio of 2:7:8 the multiplying by a constant k, we have X=2k, Y= 7k and Z=8k.
Then if  X, Y-12, Z form a Geometric sequence, it means X/Y-12=Y-12/Z which is the same as 2k/7k-12=7k-12/8k if we cross multply, we get
   16k²= 49k²-168k +144
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k = 4 or 1.091 if we take the whole number  to find the values of X,Y and z,
X= 8, Y= 28 and Z=32 
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