Rationalise the denominator√3-√5/√7-√6

Mathematics

2 answers:

krek1111 [17]2 years ago

6 0

Answer:

⇒√21+√18-√35-√30

Step-by-step explanation:

$\frac{\sqrt{3}-\sqrt{5} }{\sqrt{7}-\sqrt{6} } \\\\\frac{\sqrt{3}-\sqrt{5} }{\sqrt{7}-\sqrt{6} }*\frac{{\sqrt{7}+\sqrt{6} }}{{\sqrt{7}+\sqrt{6} }} \\\\\frac{(\sqrt{3}-\sqrt{5})*(\sqrt{7}+\sqrt{6} ) }{(\sqrt{7})^{2}-(\sqrt{6})^{2} } } \\\\\frac{\sqrt{21}+\sqrt{18} -\sqrt{35}-\sqrt{30} }{7-6}\\\\\sqrt{21}+\sqrt{18} -\sqrt{35}-\sqrt{30}$

sammy [17]2 years ago

3 0

Answer:

√21 + 3√2 - √35 - √30

Step-by-step explanation:

Given :-

√3 - √5 / √7 - √6

Solving :-

= √3 - √5 (√7 + √6) / √7 - √6 (√7 + √6)

= √21 + √18 - √35 - √30 / 7 - 6

= √21 + 3√2 - √35 - √30

Solution :-

√21 + 3√2 - √35 - √30

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