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Musya8 [376]
2 years ago
14

Rationalise the denominator√3-√5/√7-√6​

Mathematics
2 answers:
krek1111 [17]2 years ago
6 0

Answer:

⇒√21+√18-√35-√30

Step-by-step explanation:

\frac{\sqrt{3}-\sqrt{5}  }{\sqrt{7}-\sqrt{6}  } \\\\\frac{\sqrt{3}-\sqrt{5}  }{\sqrt{7}-\sqrt{6}  }*\frac{{\sqrt{7}+\sqrt{6}  }}{{\sqrt{7}+\sqrt{6}  }} \\\\\frac{(\sqrt{3}-\sqrt{5})*(\sqrt{7}+\sqrt{6} )   }{(\sqrt{7})^{2}-(\sqrt{6})^{2}   }  } \\\\\frac{\sqrt{21}+\sqrt{18} -\sqrt{35}-\sqrt{30}   }{7-6}\\\\\sqrt{21}+\sqrt{18} -\sqrt{35}-\sqrt{30}

sammy [17]2 years ago
3 0

Answer:

<u>√21 + 3√2 - √35 - √30</u>

Step-by-step explanation:

<u>Given :-</u>

√3 - √5 / √7 - √6

<u>Solving :-</u>

= √3 - √5 (√7 + √6) / √7 - √6 (√7 + √6)

= √21 + √18 - √35 - √30 / 7 - 6

= √21 + 3√2 - √35 - √30

<u>Solution :-</u>

<u>√21 + 3√2 - √35 - √30</u>

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