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Minchanka [31]
3 years ago
5

Part A: Make tables to find the solution to 4−x = 2−x+1. Take the integer values of x between −2 and 2.

Mathematics
1 answer:
BabaBlast [244]3 years ago
5 0
  Check attached image files.

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.58 + .15x = 4.78
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Ymorist [56]

the answer for this question is (B) 5,-2

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Can someone please give me the answers
Angelina_Jolie [31]

Answer:

1) 3

2)9

3)18

4)18k

5)18 and k

6)k/3

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8)3

9)9 + k/3

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3 years ago
Out of a 52 deck of cards what's the probability that you pull a card above a jack
bazaltina [42]

Answer: 3/13

Step-by-step explanation:

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7 0
3 years ago
7.<br>(-3x³)(-2x³y⁴z)(-3z²)÷(4x³z)(-3yz) (-3xyz)​
serg [7]

Answer:

-\frac{x^2y^2}{2}

Step-by-step explanation:

We have an extremely large equation and are asked to divide it, so let's solve it step-by-step :

Remove the parenthesis to make it easier to read :

\frac{-3x^3 *2x^3y^4z *3z^2}{4x^3z*3yz*3xyz}

Multiply the numerators :

\frac{-18x^6y^4z^3}{4*3*3x^3yyzzz}

Multiply the denominators :

\frac{-18x^6y^4z^3}{36x^4y^2z^3}

Apply the negative rule :

-\frac{18x^6y^4z^3}{36x^4y^2z^3}

Cancel the common factor which is 18 :

-\frac{x^6y^4z^3}{2x^4y^2z^3}

Apply the addition exponent rule :

\frac{y^4z^3x^{6-4} }{2y^2z^3}

Subtract :

\frac{x^2y^4z^3 }{2y^2z^3}

Apply the rule for y :

\frac{x^2y^{4-2} z^3 }{2z^3}

Subtract :

\frac{x^2y^2z^3 }{2z^3}

Cancel the common factor of z^3 :

-\frac{x^2y^2}{2}

5 0
3 years ago
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