[3 1 If A= -1 2] , prove that A- 5A + 71 = 0 It is matrices...

Aleksandr [31]

You would do 172 -8 and keep the i when you cancel the numbers out

3 0

1 year ago

Two random samples are taken, with each group asked if they support a particular candidate. A summary of the sample sizes and pr

Minchanka [31]

Answer:

And we got $\alpha/2 =0.01$ so then the value for $\alpha=0.02$ and then the confidence level is given by: $Conf=1-0.02=0.98[/tex[ or 98%Step-by-step explanation:A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval". The margin of error is the range of values below and above the sample statistic in a confidence interval. Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean". [tex]p_1$ represent the real population proportion for 1

$\hat p_1 =0.768$ represent the estimated proportion for 1

$n_1=92$ is the sample size required for 1

$p_2$ represent the real population proportion for 2

$\hat p_2 =0.646$ represent the estimated proportion for 2

$n_2=95$ is the sample size required for 2

$z$ represent the critical value for the margin of error

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

The confidence interval for the difference of two proportions would be given by this formula

$(\hat p_1 -\hat p_2) \pm z_{\alpha/2} \sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1} +\frac{\hat p_2 (1-\hat p_2)}{n_2}}$

For this case we have the confidence interval given by: (-0.0313,0.2753). From this we can find the margin of erro on this way:

$ME= \frac{0.2753-(-0.0313)}{2}=0.1533$

And we know that the margin of erro is given by:

$ME=z_{\alpha/2} \sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1} +\frac{\hat p_2 (1-\hat p_2)}{n_2}}$

We have all the values except the value for $z_{\alpha/2}$

So we can find it like this:

$0.1533=z_{\alpha/2} \sqrt{\frac{0.768(1-0.768)}{92} +\frac{0.646 (1-0.646)}{95}}$

And solving for $z_{\alpha/2}$ we got:

$z_{\alpha/2}=2.326$

And we can find the value for $\alpha/2$ with the following excel code:

"=1-NORM.DIST(2.326,0,1,TRUE)"

And we got $\alpha/2 =0.01$ so then the value for $\alpha=0.02$ and then the confidence level is given by: $Conf=1-0.02=0.98$ or 98%

7 0

2 years ago

Like in Utah, license plates in the great state of Wisconsin consist of 2 letter and 4 digits. However, only digits can repeat a

sveta [45]

Answer:

The correct option is B) 26x26x10^4.

Step-by-step explanation:

Consider the provided information.

It is given that the Wisconsin consist of 2 letter and 4 digits. And two letters always precede the digits.

There are 26 Alphabet so that means for alphabets we have 26 choices also we for digits we have 10 choices (0 to 9).

However, only digits can repeat. For first letter we have 26 choices for second we have only 25 choices left, similarly for digits we have 10 choices but repetition is allow so we can choose same number. the number of possible plates are:

26×25×10×10×10×10

Which also can be written as:

$26 \times 25 \times 10^{4}$

Hence, the correct option is B) 26x26x10^4.

8 0

2 years ago

A game involves rolling a fair six-sided die. If the number facing upward on the die is a whole number multiple of three, the pl

BaLLatris [955]

There is only two multiples of three on a six-sided die, the 3 side, and the 6 side.

3 x 20 = 60
6 x 20 = 120
120 + 60 = 180

$180.00 is your possible winnings total, but the question asks for your expected value on EACH roll, so you divide 180 by 6(sides on a die) to get your final answer

180/6 = 30

ANSWER: D. $30.00

5 0

2 years ago

Read 2 more answers

Helppp plsssss!!! Show your work!! Thanks

ZanzabumX [31]

First, determine if the boundary line should be dotted or solid. In this case, it should be dotted because the symbol is less than not less than or equal to. This leaves you with options B or D. Now, to see if it should be shaded up or down, test it by substituting any point, let's say the origin (0,0), to see if that point is a solution to the equation. If it is, you shade that side of the graph, but if it's not, you shade the other side of the graph.

0 is less than (-3/4)(0) + 2

0 is less than 2.

Because 0 is actually less than 2, the statement is correct and you shade below the line

Answer: D

6 0

2 years ago

[3 1If A= -1 2], prove that A- 5A + 71 = 0 It is matrices...​

[3 1If A= -1 2], prove that A- 5A + 71 = 0 It is matrices...