Answer:
<em>Given </em><em>points </em><em>are </em><em>(</em><em> </em><em>0</em><em> </em><em>,</em><em>5</em><em> </em><em>)</em><em> </em><em>and </em><em>(</em><em> </em><em>1</em><em>0</em><em> </em><em>,</em><em> </em><em>-</em><em>7</em><em>)</em>
Step-by-step explanation:
Slope ( m) = (y2 - y1) / ( x2 - x1 )
= (5+7)/(0-10)
= 12/-10
= -6/5
Using the identity sin^2(t)+cos^2(t)=1
and
given sin(t)=0.3,
we can find cos(t) by substituting
sin^2(t)+cos^2(t)=1
0.3^2+cos^2(t) = 1
cos^2(t)=1-0.3^2=1-0.09=0.91
cos(t)=sqrt(0.91)= 0.954 ≠ 0.6
So the given proposition is false.
We are asked to write an expression that uses partial products to multiply 8 and 64. In this case, we can break 8 into 2 x4 and 64 into 8x8. In this case, multiplying these factors equal to 512. Any factors will do actually since it will yield the same product
Answer:
Depends, but is either 24, 362880, and 5040, or 6, 40320, and 720.
Step-by-step explanation:
We can set each one up as x!, where ! represents factorial and x is the number of guests. This is because the first guest can choose from, say, 4 seats, and then the next guest can choose from 3 seats because one is already taken, and so one.
If your problem wants distinguishable in a way such that the table can be rotated to exclude overcounting, then we have 3!, 8!, and 7!, because for each we can rotate the table around 4, 9, and 8 ways respectively, but still get the same arrangement.
The dog groomer brought 4 packages of the packs of 5 and 3 of the Gourmet treats.
4 packages of the pack of 5 : 20 treats
3 packages of Gourmet treats : 6 treats
