Haji rows his canoe 10 mph in still water. He noticed one day that he could row 4 miles upstream in the same amount of time he c ould row 6 miles downstream. What was the approximate speed of the current that day?
2 answers:
2.0 mph
So you see that he was rowing up stream and could go 4 miles an hour, but down stream, with the push of the current gave him an extra boost of 2 miles an hour
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Calculater I'm pretty sure
Send me your email I will send the working.
Answer:
y=-2/3x+20/3
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(4-6)/(4-1)
m=-2/3
y-y1=m(x-x1)
y-6=-2/3(x-1)
y=-2/3x+2/3+6
y=-2/3x+2/3+18/3
y=-2/3x+20/3
Answer:
$6414
Step-by-step explanation:
Step one
given
Principal=$2,000
rate= 6%= 0.06
Time= 20 years
Required
The final amount
Step two:
The compound interest formula is
A= P(1+r)^t
substituting we have
The amount given to the college is $6414
Answer:
51
Step-by-step explanation:
1 mL = 0.034 fluid ounces
(500 + 1000) x 0.034
= 51 fluid ounces
