5) For this problem, convert and solve forx: logy 4096 = x

What is 5 1 2 + 2 1 7 ?

alina1380 [7]

Answer:

769

Step-by-step explanation:

512

+217

____

729

hope this helps

the fraction answer is 7 9/14 lol

4 0

2 years ago

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PLS HELP ME FAST WILL GIVE POINTS

SpyIntel [72]

Answer:

The scale factor of the dilation that transforms the triangle is 1/3

Step-by-step explanation:

9x1/3 is 3. 6x1/3 is 2, etc.

5 0

2 years ago

Find the area of this shape

Korolek [52]

Answer:

1496π square meters

Step-by-step explanation:

A=2πrh+2πr²

=2π(17)(27)+2π(17)²

= 918π + 578π

=1496π

6 0

2 years ago

EN LOS PUEBLOS DE AYLLÓN, RIAZA Y CANTALEJO DE 1200, 2100 Y 3500 HABITANTES, RESPECTIVAMENTE, SE HA SOLICITADO LA PARTICIPACIÓN

MAVERICK [17]

Answer:

???

Step-by-step explanation:

6 0

3 years ago

Which equation has the solutions x=1+or-square root of 5?

stiv31 [10]

We will proceed to solve each case to determine the solution of the problem.

case a) $x^{2}+2x+4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}+2x=-4$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}+2x+1=-4+1$

$x^{2}+2x+1=-3$

Rewrite as perfect squares

$(x+1)^{2}=-3$

$(x+1)=(+/-)\sqrt{-3}\\(x+1)=(+/-)\sqrt{3}i\\x=-1(+/-)\sqrt{3}i$

therefore

case a) is not the solution of the problem

case b) $x^{2}-2x+4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}-2x=-4$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}-2x+1=-4+1$

$x^{2}-2x+1=-3$

Rewrite as perfect squares

$(x-1)^{2}=-3$

$(x-1)=(+/-)\sqrt{-3}\\(x-1)=(+/-)\sqrt{3}i\\x=1(+/-)\sqrt{3}i$

therefore

case b) is not the solution of the problem

case c) $x^{2}+2x-4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}+2x=4$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}+2x+1=4+1$

$x^{2}+2x+1=5$

Rewrite as perfect squares

$(x+1)^{2}=5$

$(x+1)=(+/-)\sqrt{5}\\x=-1(+/-)\sqrt{5}$

therefore

case c) is not the solution of the problem

case d) $x^{2}-2x-4=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}-2x=4$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}-2x+1=4+1$

$x^{2}-2x+1=5$

Rewrite as perfect squares

$(x-1)^{2}=5$

$(x-1)=(+/-)\sqrt{5}\\x=1(+/-)\sqrt{5}$

therefore

case d) is the solution of the problem

therefore

the answer is

$x^{2}-2x-4=0$

5 0

2 years ago

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