Answer:
Step-by-step explanation:
5 game apps to 2 educational apps = 5/2
I don't have any choices given, but either 5/2 is the answer or 2.5/1 or 2 1/2:1 is the answer.
Answer:
618
Step-by-step explanation:
1st step: 6x3x412
2nd step: 7416/12
answer: 618
Complete Question
The average finishing time among all high school boys in a particular track event in a certain state is 5 minutes 17 seconds. Times are normally distributed with standard deviation 12 seconds.
a. The qualifying time in this event for participation in the state meet is to be set so that only the fastest 5% of all runners qualify. Find the qualifying time in seconds (round it to the closest second). (Hint: Convert minutes to seconds.)
b. In the western region of the state the times of all boys running in this event are normally distributed with standard deviation 12 seconds, but with mean 5 minutes 22 seconds. Find the proportion of boys from this region who qualify to run in this event in the state meet. (Hint: normalcdf)
Answer:
a
The qualifying time is
b
The proportion of boy that qualify id 0.0197 of all the boys from west region that participated in the event
Step-by-step explanation:
Considering a
The mean is \
The standard deviation is
The percentage of success is 5% =0.05
Now since the times is normally distributed the critical value of success obtained from the standardized normal distribution table is
So the qualifying time is mathematically represented as
substituting values
Considering b
The means is
Now from a the qualifying time is
Now the proportion of boys that will qualify to run in this event in the state is area under the normal curve for
substituting values
So
P(Z<=-2.06) = 0.0197
Well what u do is that u do 60 x 4 which is 240 and now just do 240 x 10 which is going to be 2400.
Hope this helps
Answer:
open circle on negative 10 with the arrow going to the right. one trick is when the variable is on the left the inequality sign points to where the arrow will go and > is open circle > with a line under is closed circle