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3 years ago

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Una compañía encuentra que su utilidad esta dada por R=2pe^-0.1p cuando au producto esta cotizado en p dolares por unidad. Encue

ntre la utilidad marginal con respecto al precio cuando p es a.) $5 b.) $10 c.) $15

1 answer:

e-lub [12.9K]3 years ago

5 0

Answer:

6.065; 7.358 ; 6.694

Step-by-step explanation:

Given that, profit is quoted using the function :

R = 2pe ^ -0.1p

(a)

When price 'p' = $5

R = 2(5)e^(-0.1*5)

R = 10e^(-0.5)

R = 10 * 0.6065306

R = 6.065

B)

When price 'p' = $10

R = 2(10)e^(-0.1*10)

R = 20e^(-1)

R = 20 * 0.3678794

R = 7.358

C.)

When price 'p' = $15

R = 2(15)e^(-0.1*15)

R = 30e^(-1.5)

R = 30 * 0.2231301

R = 6.694

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Other method.

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3 years ago

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The constant of proportionality is 1,250 the 5/6 is 6,250. You have to now find out the 10% by multiplying it which = 625. 625 is not the amount that they can sell that is the amount that they gave to the players and staff. So now you have to subtract 625 from 6,250 which would give you 5,625 strawberry's.

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3 years ago

Savannah and her children went into a grocery store and she bought $22 worth of

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Answer:

Step-by-step explanation:

p = peaches, m = mangos

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2 years ago

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3 years ago

An environmental engineer is tasked with determining whether a power plant cooling system is heating the water it uses more than

Tpy6a [65]

Answer:

1

The correct option is b

2

The correct option is h

Step-by-step explanation:

From the question we are told that

The sample size is n = 15

The difference in population proportion is $d = 6$

Generally the sample mean of the input temperature is

$\= x_1 = \frac{\sum x_i }{n}$

=> $\= x_1 = \frac{57.6 + 68.9 + \cdots +60.4 }{15}$

=> $\= x_1 = 62.57$

Generally the sample mean of the output temperature is

$\= x_2 = \frac{\sum x_i }{n}$

=> $\= x_2 = \frac{65.1 + 74.4 + \cdots +67.3 }{15}$

=> $\= x_2 = 55.97$

Generally the difference of the sample mean of the input temperature and that of the output temperature is

$\= d = \= x_1 - \= x_2$

=> $\= d = 62.57 -55.97$

=> $\= d = 6.6$

Generally the standard deviation is mathematically represented as

$s_d = \sqrt{\frac{\sum(d_1 - \= d )^2}{n} }$

=> $s_d = \sqrt{\frac{([57.6- 65.1]- 6.6)^2+ ([68.9 - 74.4]- 6.6)^2 + \cdots + ([60.4 - 67.3]- 6.6)^2 }{15} }$

=> $s_d = 1.732 [/texGenerally the test statistics is mathematically represented as [tex]t = \frac{ d - \= d }{ \frac{s_d}{\sqrt{n} } }$

=> $t = \frac{ 6-6.6 }{ \frac{1.732}{\sqrt{15} } }$

=> $t = 1.3417$

Generally the degree of freedom is mathematically represented as

$df = n - 1$

=> $df = 15 - 1$

=> $df = 14$

Generally the probability of t obtained from the t - distribution table at a degree of freedom of $df = 14$ is

$P(t >1.3417 ) = 0.10052569$

Generally the p-value is mathematically represented as

$p-value = 2 * P(t > 1.3417)$

=> $p-value = 2 * 0.10052569$

=> $p-value = 0.201$

From the values obtained we see that $p-value > \alpha$ hence

The decision rule is

Fail to reject the null hypothesis

The conclusion is

The cooling system changes the temperature of the water by 6 degrees.

8 0

3 years ago