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d1i1m1o1n [39]
3 years ago
13

Does anybody know how to find area of a triangle?

Mathematics
2 answers:
belka [17]3 years ago
7 0

Explanation:

<h2>Hello, I’m here to help you! </h2>

➡ Pythagorean Theorem: a² + b² = c²

➡ We eliminate D - So the Pythagorean theorem is used for right triangles and that equation is a² + b² = c² and answer D doesn't have anything squared.

➡ Hypotenuse is what letter in the theorem? It is Letter C!

➡ 11² + 60² = 3721

<h2>The correct Option is C. </h2>

Hope this helps! :)

meriva3 years ago
6 0

Answer:

Step-by-step explanation:

area = 1/2 x base x height

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Convert 4x-2y=6 into slope intercept form
DanielleElmas [232]

Answer:

y=2x-3

Step-by-step explanation:

first, you have to get the y by itself (isolate the y). you do this by subtracting 4x from both sides.

4x-2y=6

-2y=-4x+6

next, you have to divide both side by -2 to isolate the y further and get this into slope-intercept form:

-2y=-4x+6

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3 years ago
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erastova [34]

Answer:

5/2<x<5

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-7<3-2x<-2

or -7-3<-2x<-2-3

or -10<-2x<-5

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3 years ago
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Natasha_Volkova [10]

Answer:

\frac{\sqrt{110} }{11} or \frac{\sqrt{10} }{\sqrt{11} }

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I assume you mean \frac{9\sqrt{10} }{9\sqrt{11} }

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multiply \frac{\sqrt{10} }{\sqrt{11} } by some form of 1. this case, we will use \frac{\sqrt{11} }{\sqrt{11} } as our 1.

\frac{\sqrt{10} }{\sqrt{11} }*\frac{\sqrt{11} }{\sqrt{11} } = \frac{\sqrt{10} *\sqrt{11} }{\sqrt{11} *\sqrt{11} } = \frac{\sqrt{110} }{11}

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3 years ago
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shusha [124]

Answer:

g=2

Step-by-step explanation:

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2. divide 2 from both sides

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5 0
3 years ago
Read 2 more answers
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