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2 years ago

Does anybody know how to find area of a triangle?

Mathematics

2 answers:

belka [17]2 years ago

7 0

Explanation:

<h2>Hello, I’m here to help you! </h2>

➡ Pythagorean Theorem: a² + b² = c²

➡ We eliminate D - So the Pythagorean theorem is used for right triangles and that equation is a² + b² = c² and answer D doesn't have anything squared.

➡ Hypotenuse is what letter in the theorem? It is Letter C!

➡ 11² + 60² = 3721

<h2>The correct Option is C. </h2>

Hope this helps! :)

meriva2 years ago

6 0

Answer:

Step-by-step explanation:

area = 1/2 x base x height

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9. You have a bag with 3 red marbles, 4 blue marbles, and 5 green marbles. You draw 2 marbles out of the bag. Without replacing

uysha [10]

P(BB)=(4/12)(3/11)=12/132=1/11

P(RG)=(3/12)(5/11)=15/132=5/44

4 0

2 years ago

Read 2 more answers

Kamal wrote the augmented matrix below to represent a system of equations

Alina [70]

Consider the operation is $R_2\to -3R_2$ .

Given:

The augmented matrix below represents a system of equations.

$\left[\left.\begin{matrix}1&0&1\\1&3&-1\\3&2&0\end{matrix}\right|\begin{matrix}-1\\-9\\-2\end{matrix}\right]$

To find:

Matrix results from the operation $R_2\to -3R_2$ .

Step-by-step explanation:

We have,

$\left[\left.\begin{matrix}1&0&1\\1&3&-1\\3&2&0\end{matrix}\right|\begin{matrix}-1\\-9\\-2\end{matrix}\right]$

After applying $R_2\to -3R_2$ , we get

$\left[\left.\begin{matrix}1&0&1\\-3(1)&-3(3)&-3(-1)\\3&2&0\end{matrix}\right|\begin{matrix}-1\\-3(-9)\\-2\end{matrix}\right]$

$\left[\left.\begin{matrix}1&0&1\\-3&-9&3\\3&2&0\end{matrix}\right|\begin{matrix}-1\\27\\-2\end{matrix}\right]$

Therefore, the correct option is A.

7 0

3 years ago

Show me how to do this please for geometry!!

ololo11 [35]

Answer:

see explanation

Step-by-step explanation:

Since the triangles are right use trigonometric ratios to find x and y

sin33° = $\frac{adjacent}{hypotenuse}$ = $\frac{2.5}x}$

Multiply both sides by x

x × sin33° = 2.5 ( divide both sides by sin33° )

x = $\frac{2.5}{sin33}$ ≈ 4.590

tan33° = $\frac{opposite}{adjacent}$ = $\frac{2.5}{y}$

Multiply both sides by y

y × tan33° = 2.5 ( divide both sides by tan33° )

y = $\frac{2.5}{tan33}$ ≈ 3.850

cos72° = $\frac{adjacent}{hypotenuse}$ = $\frac{6}{x}$

Multiply both sides by x

x × cos72° = 6 ( divide both sides by cos72° )

x = $\frac{6}{cos72}$ ≈ 19.416

tan72° = $\frac{y}{6}$

Multiply both sides by 6

6 × tan72° = y, thus

y ≈ 18.466

4 0

3 years ago

What is f(x)=2x^2+3x+7 is x=-5

Mice21 [21]

F(-5) = 2(-5)² + 3(-5) + 7
f(-5) = 2(25) - 15 + 7
f(-5) = 50 - 8
f(-5) = 42

4 0

3 years ago

In a department store the owner paid $15 for 1kg of sugar.The owner marked the price up by 10% for the customers.How much dose h

oee [108]

First, we need to figure out 10% of fifteen.

So, we multiple 15 by 10% (or 0.1 in simpler terms).

That gives us 1.5, which is our mark-up price.

So, finally we add the markup price to the original price to obtain the selling price.

1.5 + 15 = 16.5

The owner charges $16.50 for 1kg of sugar!

5 0

3 years ago