Find measure of angle BDC

Mathematics

1 answer:

Liula [17]2 years ago

4 0

The 2 angles are complemantary or form right angles so $-3x+20-2x+55=90=-5x+75=90=-5x=15
$ so $x=3$ . Plugging that into BDC we get 11

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WILL GIVE BRAINLIEST

puteri [66]

Step-by-step explanation:

${EF}^{2} = {EG}^{2} - {FG}^{2} \\ \\ = {8}^{2} - {6}^{2} \\ \\ = 64 - 36 \\ \\ = 28 \\ \\ \therefore \: {EF} = \sqrt{28} \\ \\ \therefore \: {EF} = 2\sqrt{7} \\ \\ \sin \: E = \frac{FG }{EG} = \frac{6}{8} = \frac{3}{4} \\ \\ \huge\red {\boxed{\therefore \: \sin \: E = \frac{3}{4}} } \\\sec \: G = \frac{ EG}{FG} = \frac{8}{6} = \frac{4}{3} \\ \\ \huge\purple {\boxed{ \therefore \: \sec \: G = \frac{4}{3}}} \\\\\cot \: G = \frac{ FG}{EF} = \frac{6}{2\sqrt 7} = \frac{3}{\sqrt 7} \\ \\ = \frac{3\times\sqrt 7 }{\sqrt 7\times\sqrt 7 } \\ \\ = \frac{3\sqrt 7 }{ 7 } \\ \\ \huge\orange {\boxed{ \therefore \: \cot \: G = \frac{3\sqrt 7 }{ 7 } }} \\\\$