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Ymorist [56]
3 years ago
7

Find measure of angle BDC

Mathematics
1 answer:
Liula [17]3 years ago
4 0
The 2 angles are complemantary or form right angles so -3x+20-2x+55=90=-5x+75=90=-5x=15
 sox=3. Plugging that into BDC we get 11
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Simplify each write as a smaller fractions or mixed number 6 / 18
miv72 [106K]
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3 years ago
Solve for x in the equation X^2 - 8X + 41= 0
BaLLatris [955]

Answer:

The equation has two solutions for x:

<u>x₁ = (8 + 10i)/2</u>

<u>x₂ = (8 - 10i)/2</u>

Step-by-step explanation:

Let's use the quadratic formula for solving for x in the equation:

X^2 - 8X + 41= 0

x² - 8x + 41 = 0

Let's recall that the quadratic formula is:

x = -b +/- (√b² - 4ac)/2a

Replacing with the real values, we have:

x = 8 +/-  (√-8² - 4 * 1 * 41)/2 * 1

x = 8 +/-  (√64 - 164)/2

x = 8 +/-  (√-100)/2

x = 8 +/-  (√-1 *100)/2

Let's recall that √-1 = i

x = 8 +/- 10i/2

<u>x₁ = (8 + 10i)/2</u>

<u>x₂ = (8 - 10i)/2</u>

8 0
3 years ago
Consider the graph of the line y = x – 4 and the point (−4, 2).
Hitman42 [59]

Answer:

a. The slope  of a line parallel to the given line is 1

b. A point on the line parallel to the given line, passing through (−4, 2), is  (1,7)

c. The slope of the line perpendicular to the given line is -1

d. A point on the line perpendicular to the given line, passing through (−4, 2), is (3,-5)

Step-by-step explanation:

The equation of the line in Slope-intercept form  is:

y=mx+b

Where m is the slope and b is the y-intercept.

a. For the line y = x - 4

You can identify that:

m=1

 By definition, two lines are parallel if they have the same slope. Then, the  slope of a line parallel to the given line is:

m=1

b. The equation of the line in Point-slope form is:

y -y_1 = m(x - x_1)

Where m is the slope and (x_1,y_1)  is a point of the line.

Given the point (-4,2), substitute this point and the slope of the line into the equation:

 y -2 = (x +4)

Give a value to "x", substitute it into this equation and solve for "y":

For x=1 :

y -2 = (1 +4)

y= 5+2

y= 7

Then, you get the point (1,7)

c. The slopes of perpendicular lines are negative reciprocals, then the  slope of a line perpendicular to the given line is:

m=-\frac{1}{1}\\\\m=-1

d. Given the point (-4,2), substitute this point and the slope of the line into the equation:

 y -2 = -1(x +4)

 y -2 = -(x +4)

Give a value to "x", substitute it into this equation and solve for "y":

For x=3 :

y -2 = -(3 +4)

y= -7+2

y= -5

Then, you get the point (3,-5)

8 0
3 years ago
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