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3 years ago

My noob has 36 apples he puts 29 in a bag how much he has now

Mathematics

1 answer:

SCORPION-xisa [38]3 years ago

8 0

Answer: He has 7 at the moment, technically, if he still has the bag, he still has all 36

Step-by-step explanation:

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Given the function f(x) = 6x2 + 3 Find f(-2) -22 27 9 15

Andrews [41]

Answer:

Step-by-step explanation:

Out of those numbers and assuming the equation is f(x) = 6x^2=3

f(-2)= 6(-2)^2+3

8 0

3 years ago

(1.2×10^2) + (3.04×10^5)

PSYCHO15rus [73]

(1.2×10^2) + (3.04×10^5)

They must be to the same power to add

3.04 *10^5 to change to the 2nd power (5-2=3) move the decimal 3 places to the right = 3040. * 10^2

1.2 * 10^2 + 3040 *10^2=

add the numbers keep the exponents the same

3041.2 * 10^2

there can only be 1 number before the decimal in scientific notation so we need to move the decimal 3 places to the left, which adds 3 to the exponent

3.0412 * 10 ^ (2+3)

3.0412 * 10^5

8 0

3 years ago

X/5=2/3=5/y 2/3 4/9 1

Mademuasel [1]

$\frac{x}{5}= \frac{2}{3} = \frac{5}{y}$
Break the equation into parts;
$\frac{x}{5} = \frac{2}{3} ; \frac{2}{3}= \frac{5}{y}$
Solving for x;
$\frac{x}{5} = \frac{2}{3}$
x= $\frac{10}{3}$
Solving for y;
$\frac{2}{3} = \frac{5}{y} 
y= \frac{3*5}{2} 
y= \frac{15}{2}$
$\frac{x}{y} = \frac{10/3}{15/2}$
$\frac{x}{y} = \frac{4}{15}$

5 0

3 years ago

The school store opened on the first day of school with 45 notebooks and 15 pencils. Within two days it sold all of these items.

malfutka [58]

The number of pencils sold on the first day is 5 pencils.

The number of notebooks sold on the first day is 10 notebooks.

The number of pencils sold on the second day 10 pencils.

The number of notebooks sold on the second day 35 notebooks.

Step-by-step explanation:

Given data,

The total number of notebooks in the store = 45 notebooks.
The total number of Pencils in the store = 15 pencils.
The number of days that all items were sold = 2 days.

Now, you have to calculate the no.of notebooks and no. of pencils sold each day.

In the first day :

The number of sale of notebooks and pencils are given by,

Twice as many notebooks were sold as pencils.

Let us take, the number of pencils sold on the first day = x

And, the number of notebooks sold on the first day = 2x (Twice as pencils).

In the second day :

The number of sale of notebooks and pencils are given by,

For every 7 notebooks sold, 2 pencils were sold.

The number of pencils sold on the second day = 2y

The number of notebooks sold on the second day = 7y

The equation is framed for number of notebooks sold on each day :

The number of notebooks sold ⇒ 2x + 7y = 45 -------(1)

The equation is framed for number of pencils sold on each day :

The number of pencils sold: x + 2y = 15 ----------(2)

Solving the equations by multiplying eq(2) by 2 and subtract it from eq(1),

2x + 7y = 45

- (2x + 4y) = 30

3y = 15

⇒ y = 15/3

⇒ y = 5

The value of y is 5.

Substitute y=5 in eq (2),

⇒ x + 2(5) = 15

⇒ x + 10 = 15

⇒ x = 15 - 10

⇒ x = 5

The value of x is 5.

First day sale,

The number of pencils sold on the first day = x ⇒ 5 pencils

The number of notebooks sold on the first day = 2x ⇒ 10 notebooks

Second day sale,

The number of pencils sold on the second day = 2y ⇒ 10 pencils

The number of notebooks sold on the second day = 7y ⇒ 35 notebooks.

8 0

2 years ago

I need help with this problem

yKpoI14uk [10]

-24 + y= -120

y= -96 is the answer to the problem

6 0

3 years ago

Read 2 more answers