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3 years ago

How many cubic inches of water will a spherical water ballon hold with a surface area of 113.04

Mathematics

1 answer:

marusya05 [52]3 years ago

7 0

Answer:

boop :[

Step-by-step explanation:

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In the isosceles triangle ABC, we have AB=AC=4. The altitude from B meets AC at H. If AH=3(HC) then determine BC.

Inga [223]

Answer:

BC=√7

Step-by-step explanation:

AC=4

AC=AH+HC

=3HC+HC

=4HC

HC=1/4AC=1/4×4=1

AH=3HC=3×1=3

BH⊥ AC

AB=AC=4

$BC=\sqrt{AB^2-AH^2} =\sqrt{4^2-3^2} =\sqrt{16-9} =\sqrt{7}$

5 0

3 years ago

Which of the following equations has the given solution set?

tester [92]

-2m + 5 = 2m + 5
2m + 2m = 5 - 5
4m = 0
m = 0

-2m + 5 = -2m + 5
-2m + 2m = 5 - 5
0 = 0

-2m + 5 = -2m - 5
-2m + 2m = 5 + 5
0 = 10
Solution set is Ф
The third equation is the correct answer.

8 0

3 years ago

mr. Flanders drives 1 2/3 miles to school and 1 2/3 miles home each day he also drives an extra 2 2/7 miles to go to the gym how

Alina [70]

The answer is six and two out of seven or 6 and two sevenths

5 0

3 years ago

(4) A spherical balloon is being inflated so that its diameter is increasing at a constant rate of 6 cm/min. How quickly is the

fredd [130]

In terms of its radius $r$ , the volume of the balloon is

$V(r)=\dfrac{4\pi}3r^3$

The diameter $d$ is twice the radius, so that in terms of its diameters, the balloon's volume is given by

$V(d)=\dfrac{4\pi}3\left(\dfrac d2\right)^3=\dfrac\pi6d^3$

Differentiate both sides with respect to time $t$ :

$\dfrac{\mathrm dV}{\mathrm dt}=\dfrac\pi2d^2\dfrac{\mathrm dd}{\mathrm dt}$

The diameter increases at a rate of $\frac{\mathrm dd}{\mathrm dt}=6\frac{\rm cm}{\rm min}$ . When the diameter is $d=50\,\mathrm{cm}$ , we have

$\dfrac{\mathrm dV}{\mathrm dt}=\dfrac\pi2(50\,\mathrm{cm})^2\left(6\frac{\rm cm}{\rm min}\right)=7500\pi\dfrac{\mathrm{cm}^3}{\rm min}$

or about 23,562 cc/min (where cc = cubic centimeters)

5 0

3 years ago

1/2 (12+8) • 52 - 17=_

qwelly [4]

The answer to your question is 503

5 0

3 years ago

Read 2 more answers