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Vanyuwa [196]
3 years ago
13

Find the first and second derivatives of the function y = sin(x^2)

Mathematics
1 answer:
exis [7]3 years ago
7 0
Y = sin(x^2)

Use the chain rule.

We want dy/dx.

dy/dx = cos(x^2)*2x

dy/dx = 2xcos(x^2)

Did you follow?
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