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storchak [24]
4 years ago
15

Which expression is equivalent to

Mathematics
2 answers:
ira [324]4 years ago
5 0

Answer:

= \frac{15}{25}  {m}^{2}  {n}^{3}  \\

Step-by-step explanation:

\sqrt{ \frac{225}{625} {m}^{4}   {n}^{6} } \\  \sqrt{ \frac{15 \times 15}{25 \times 25} \times m \times m \times m \times m \times n \times n \times n \times n \times n \times n }   \\  =  \frac{15}{25}  \times m \times m \times n \times n \times n \\  =  \frac{15}{25}  {m}^{2}  {n}^{3}

hope this helps

brainliest appreciated

good luck! have a nice day!

noname [10]4 years ago
4 0

Answer:

3/5 m^2 n^3

Step-by-step explanation:

√225 = 15

√625 = 25

√m^4 = m^2

√n^6 = n^3

Put it all together and you get 15/25 m^2 n^3

Simplify 15/25 to 3/5

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5 0
3 years ago
For concreatting a tower cement, sand, stones are in the ratio 1:2:4 For 144kg sand.. What amount of cement is required?
Verdich [7]

Answer:

72 kg

Step-by-step explanation:

For concreatting a tower cement, sand, stones are in the ratio 1:2:4 For 144kg sand.. What amount of cement is required?

We are given the ratio

cement: sand:stones

= 1:2:4

The sum of proportion =

1 + 2 + 4 = 7

We are given the kg of sand = 144kg

Step 1

We find the total kg of cement, sand and stones = x

Using the proportion of sand,

2/7 of x = 144kg

2/7 × x = 144kg

2x/7 = 144kg

Cross Multiply

2x = 7 × 144kg

x = 7 × 144kg/2

x = 504kg

Therefore the total kg of cement, sand and stone = 504kg

Step 2

The amount of cement required is calculated as:

1/7 × 504 kg = 72 kg

Therefore, 72kg of cement is required.

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