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Jet001 [13]
2 years ago
8

Factorize: t2 + 6 + 8

Mathematics
1 answer:
Mnenie [13.5K]2 years ago
4 0

t²+14

Step-by-step explanation:

<h2>..........</h2>
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Pls help me 2x-3=y pls pls pls
Murrr4er [49]

What is the instruction?

6 0
3 years ago
a school band gives a year end concert. it is held in a 400 seat auditorium. each convert ticket sells for $10, and 85% of the t
dmitriy555 [2]
400 seats x .85 = 340 tickets sold
340 x $10 = $3,400
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3 years ago
In order to study the relationship between playing football and traumatic brain injuries, researchers placed accelerometers in t
disa [49]

Answer:

56.96% probability on a randomly selected team of 48 players that the average number of head hits per player is between 340 and 360 hits

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a single player:

\mu = 355, \sigma = 80

For the sample mean(of 48 playes).

n = 48, s = \frac{80}{\sqrt{48}} = 11.547

What is the probability on a randomly selected team of 48 players that the average number of head hits per player is between 340 and 360 hits?

This is the pvalue of Z when X = 360 subtracted by the pvalue of Z when X = 340. So

X = 360

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{360 - 355}{11.547}

Z = 0.43

Z = 0.43 has a pvalue of 0.6664

X = 340

Z = \frac{X - \mu}{s}

Z = \frac{340 - 355}{11.547}

Z = -1.30

Z = -1.30 has a pvalue of 0.0968

0.6664 - 0.0968 = 0.5696

56.96% probability on a randomly selected team of 48 players that the average number of head hits per player is between 340 and 360 hits

4 0
2 years ago
Plz answer these 2 questions hurry
yawa3891 [41]
1: answer is 8a+24b
2: answer is 6x+33y
7 0
3 years ago
Bought a box 6 in long, 10 in wide and 4 in high. How much would it cost to cover with material that cost $0.25 per square in?
german
Multiply 6x10x4 to find the volume. Which equals 240. That's 240 square inches. Multiply 240 by 0.25 and you get the cost.
6 0
3 years ago
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