<u>Answer:</u> The amount of oxygen gas consumed is 0.525 moles
<u>Explanation:</u>
We are given:
Moles of propane burned = 0.150 moles
The chemical equation for the combustion of propane follows:
By Stoichiometry of the reaction:
1 mole of propane reacts with 5 moles of oxygen gas
So, 0.150 moles of propane will react with = 
of oxygen gas
Hence, the amount of oxygen gas consumed is 0.525 moles
Answer:
-162,5 kJ/mol
Explanation:
Cl(g) + 2O2(g) --> ClO(g) + O3(g) ΔH = 122.8 kJ/mol (as we used the reaction in the opposite direction, it will turn the enthalpy from exothermic to endothermic)
2O3(g) --> 3O2(g) ΔH = -285.3 kJ/mol
Cl(g) + O2(g) --> ClO(g) + O3(g) ΔH = 122.8 kJ
+ 2O3 (g) --> 3O2(g) ΔH = - 285.3 kJ
O3(g) + Cl(g) --> ClO(g) + 2O2(g) ΔH = 122.8 + (-285.3) = -162,5 kJ
V= 50. L n=45 mol T= 200°C = 473k P=?
CP)X 50.L)= (45 mol)(0.0821 light_kimol)(473k)
P = 30am or 4000 kPa
Brainless answer:
I think it is ionic.. I am not sure
Answer:
synthesis
it's the reaction of bringing two atoms into one
Na + Cl --> Nacl
or more generally
A + B --> AB
